Log 3(x²+6x)=log(2x+12). I assume that 3 is a factor of a log with base 10:
if so, then:
log(3x²+18x)=log(2x+12)
==> 3x²+18x=2x+12==> 3x²+16x-12 = 0
solve this quadratic equation & you will find: x'=2/3 & x"=-6
The answer is f(2y) = 8y^2 - 8
In order to find this, we need to put 2y in where x was in the original equation. From there, we follow the order of operations to simplify.
f(x) = 2x^2 - 8
f(2y) = 2(2y)^2 - 8
f(2y) = 2(4y^2) - 8
f(2y) = 8y^2 - 8
Answer:16.5 feet long shadow coming from the woman...
Step-by-step explanation:add 3 to 13.5.
13.5+1=14.5
+1=15.5
+1= 16.5
Okay! When you are ready, let me know what you need help with. Just comment this answer!
It is left on the number pad on the quadratic forumla