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Illusion [34]
3 years ago
7

Please help

Mathematics
1 answer:
OlgaM077 [116]3 years ago
4 0
First, we're going to see the candies per minute that machine C packs.
150 / 2 = 75

Now that we know that machine C packs 75 candies per minute, we're going to multiply the candies machine C makes by 11 minutes.
75 x 11 = 825

We're now gonna do the same with machine D.
130 x 11 = 1430

Then we're going to find the difference between machine C and machine D, we do this because the question basically asks how much more candies can machine D pack than machine C.
1430 - 825 = 605 candies.

This is how we find our final answer.

Our answer would be D) 605.

Hope this helps!~
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Retro Rides is a club for owners of vintage cars and motorcycles. Every year the club gets together for a ride. This year, 53 ve
kari74 [83]
21 cars, 32 motorcycles.
create a system of equations using x for cars and y for motorcycles.
\left \{ {{x+y=53} \atop {4x+2y=148}} \right.
multiply the top equation by 2 to prepare for elimination method
\left \{ {{2x+2y=106} \atop {4x+2y=148}} \right.
subtract terms
\left \{ {{2x+2y=106} \atop {-4x-2y=-148}} \right.  = (-2x = -42)
divide both sides by negative 2 to solve for x
x =21
plug in x  into original equation to solve for y.
21 + y = 53
subtract both sides by 21
y=32



8 0
3 years ago
Write an equation where the left side is your power of 10 times n and the right side is the result of multiplying 0.1515... by t
Neko [114]

Answer:

n10^x = 0.1515x

Step-by-step explanation:

Required

Translate the statements to algebraic expression

Represent the power with x;

So, the left hand side is

<em>Power of 10: </em>10^x<em />

<em>Times n: </em>10^x * n<em />

<em />

The right hand side is:

<em>0.1515 * power of 10: </em>0.1515 * x<em />

Equate the right hand side to the left:

10^x * n = 0.1515 * x

n10^x = 0.1515x

Hence;

<em>The required expression is </em>n10^x = 0.1515x<em />

5 0
3 years ago
Micheal-anthony and jocelyn are both running around the track at school. michael-anthony runs 3 miles in 20mins and continues ru
alexgriva [62]

Answer:

Jocelyn = 8 Miles an Hour

Micheal-Anthony = 6 Miles a Hour

Jocelyn Run Faster than Micheal-Anthony.

Step-by-step explanation:

Important information:

Michael-Anthony runs 3 Miles in 20 Minutes.

Jocelyn Runs 4 Miles in 30 Minutes.

Continues at pace for 1 Hour.

Questions that Need to be Answer:

How many miles does each person each person run in an hour?

Who runs faster?

Explanation/Solution:

So, We know that 1 Hour = 60 Minutes and three 20 minutes equal 60 Minutes also known as 1 Hour..

Since, three 20 minutes equal 1 Hour that means

Micheal-Anthony Run 6 Miles a Hour adding the 20 Minutes equal 9 Miles

Hence, Micheal-Anthony Run 9 Miles..

We know that 1 Hour = 60 Minutes and two 30 Minutes equal 60 Minutes also known as 1 Hour..

Since, two 30 Minutes equal 1 Hour that means

Jocelyn Run 8 Miles a Hour adding the 30 Minutes equal 12 Miles

Hence, Jocelyn Run 12 Miles..

For these Reason, You can tell that Jocelyn Run 8 Miles an Hour and Micheal-Anthony Run 6 Miles a Hour and Jocelyn Run Faster than Micheal-Anthony.

8 0
2 years ago
An account with $600 earns 4% simple interest per year. The next year all the money is put into a new account that earns 4.5% si
N76 [4]
[First Year]
$600 • 0.04 • 1 year
600 • 0.04 = 24 • 1 = 24

[Second Year]
$600 • 0.045 • 1 year
600 • 0.045 = 27 • 1 = 27

24 + 27 = $51

I believe this is correct and I hope this helps! :)
7 0
3 years ago
Read 2 more answers
The path of water from a hose on a fire tugboat can be approximated by the equation y=-0.0055x^2 +1.15x + 5, where y is the heig
Komok [63]

Answer:

The water is 208.22ft from the tug boat

Step-by-step explanation:

The governing equation is y=-0.0055x^2 +1.15x + 5

y is the height above the ocean

x is the distance from the tugboat

if y= 6ft, the equation will now become

6=-0.0055x^2 +1.15x + 5

we can arrange this properly to form a quadratic equation by grouping like terms.

-0.0055x^2 +1.15x -1=0

solving quadratically we have two values of x as  208.22ft and 0.873 ft.

We can take a more realistic value as a solution to our problems:

208.22ft

6 0
3 years ago
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