Question

If f(x) =2x^2-8, what is f(2y)

Answer 1

The answer is f(2y) = 8y^2 - 8

In order to find this, we need to put 2y in where x was in the original equation. From there, we follow the order of operations to simplify.

f(x) = 2x^2 - 8

f(2y) = 2(2y)^2 - 8

f(2y) = 2(4y^2) - 8

f(2y) = 8y^2 - 8