3 years ago

If f(x) =2x^2-8, what is f(2y)

1 answer:

3 0

The answer is f(2y) = 8y^2 - 8

In order to find this, we need to put 2y in where x was in the original equation. From there, we follow the order of operations to simplify.

f(x) = 2x^2 - 8

f(2y) = 2(2y)^2 - 8

f(2y) = 2(4y^2) - 8

f(2y) = 8y^2 - 8

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