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3 years ago

Fill in the missing numbers to complete the linear equation that gives the rule for this table x f(x) 0 -28 1 -17 2 -6 3 5

Mathematics

2 answers:

pickupchik [31]3 years ago

6 0

Fill in the missing numbers to complete the linear equation that gives the rule for this table x f(x) 0 -28 1 -17 2 -6 3 5

ser-zykov [4K]3 years ago

6 0

Bonk gang whole lotta gang shut my nihha I got it like I got it but I can’t say though cause I’m on all kind of drugs

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Marry Emma earned $45.00 babysitting her cousin. She saved $18.50 and spent the remainder. How much did Mary Emma spend?

gizmo_the_mogwai [7]

Answer:

She spent $26.50

Step-by-step explanation:

subtract $18.50 from $45.00

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2 years ago

Help with this exponential function!

butalik [34]

The population size after 6 years and after 8 years are 147 and 169 population respectively

<h3>Exponential functions</h3>

The standard exponential function is expressed as y = ab^x

where

a is the base

x is the exponent

Given the function that represents the population size P (t) of the species as shown;

$p(t)=\frac{550}{1+5e^{-0.1t}} \\$

For the population size after 6 years

$p(t)=\frac{550}{1+5e^{-0.1(6)}} \\P(6)=\frac{550}{3.744}\\ P(6)=147 population$

For the population after 8 years

$p(t)=\frac{550}{1+5e^{-0.1(8)}} \\P(8)=\frac{550}{3.2466}\\ P(8)=169 population$

Hence the population size after 6 years and after 8 years are 147 and 169 population respectively

Learn more on exponential function here: brainly.com/question/2456547

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2 years ago

Titus had 1/2 can of paint. He used 2/3 to paint a tabletop. What fraction of a full can of paint did Titus use?

dimaraw [331]

I think its 1 1/6 idk

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3 years ago

HELPPP FASTTT!!!!!!!

goldfiish [28.3K]

I cant see the picture i can’t help sorry

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3 years ago

Hey can you help me answer this question by giving me the answer?

Leto [7]

The value of f(a)=4-2a+6 $a^{2}$ , f(a+h) is $6a^{2} +6h^{2} -2a-2h+12ah$ , [f(a+h)-f(a)]/h is 6h+12a-2 in the function f(x)=4-2x+6 $x^{2}$ .

Given a function f(x)=4-2x+6 $x^{2}$ .

We are told to find out the value of f(a), f(a+h) and [f(a+h)-f(a)]/hwhere h≠0.

Function is like a relationship between two or more variables expressed in equal to form.The value which we entered in the function is known as domain and the value which we get after entering the values is known as codomain or range.

f(a)=4-2a+6 $a^{2}$ (By just putting x=a).

f(a+h)== $4-2(a+h)+6(a+h)^{2}$

=4-2a-2h+6( $a^{2} +h^{2} +2ah$ )

=4-2a-2h+6 $a^{2} +6h^{2} +12ah$

= $6a^{2} +6h^{2}-2a-2h+12ah$

[f(a+h)-f(a)]/h=[ $6a^{2} +6h^{2}-2a-2h+12ah$ -(4-2a+6 $a^{2}$ )]/h

= $(6a^{2} +6h^{2} -2a-2h+12ah)/h$

= $(6h^{2} -2h+12ah)/h$

=6h+12a-2.

Hence the value of function f(a)=4-2a+6 $a^{2}$ , f(a+h) is $6a^{2} +6h^{2} -2a-2h+12ah$ , [f(a+h)-f(a)]/h is 6h+12a-2 in the function f(x)=4-2x+6 $x^{2}$ .

Learn more about function at brainly.com/question/10439235

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2 years ago