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2 years ago

What is the volume of this figureThanks a lot! :)

Mathematics

2 answers:

AlexFokin [52]2 years ago

7 0

Answer- 1,200
Explanation- the formula of volume is length x width x height. So you just multiply those three numbers. Hope this helped!

worty [1.4K]2 years ago

7 0

Answer:

2040 in.²

Step-by-step explanation:

You would divide the figure into two rectangular prisms and solve separately.

So,

5*20*12=1200

5*14*12=840

1200+840=2040

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Middle school question.

Pavel [41]

(the answer is on the picture. is this correct?) ^^'

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1 year ago

What is the equation of the line passing through the points (1,-5) and (9,11)

Colt1911 [192]

Answer:

y=2x-7

Step-by-step explanation:

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3 years ago

After eating at your favorite restaurant,you know that the bill before tax is $52.60 and that the sales tax rate is 8%. You deci

slega [8]

The total bill would be 67.32 because you have to multiply the tax and tip then add them together

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2 years ago

Read 2 more answers

Please consider the following values for the variables X and Y. Treat each row as a pair of scores for the variables X and Y (wi

Studentka2010 [4]

Answer:

The Pearson's coefficient of correlation between the is 0.700.

Step-by-step explanation:

The correlation coefficient is a statistical degree that computes the strength of the linear relationship amid the relative movements of the two variables (i.e. dependent and independent).It ranges from -1 to +1.

The formula to compute correlation between two variables X and Y is:

$r(X, Y)=\frac{Cov(X, Y)}{\sqrt{V(X)\cdot V(Y)}}$

The formula to compute covariance is:

$Cov(X, Y)=n\cdot \sum XY-\sum X \cdot\sum Y$

The formula to compute the variances are:

$V(X)=n\cdot\sum X^{2}-(\sum X)^{2}\\V(Y)=n\cdot\sum Y^{2}-(\sum Y)^{2}$

Consider the table attached below.

Compute the covariance as follows:

$Cov(X, Y)=n\cdot \sum XY-\sum X \cdot\sum Y$

$=(5\times 165)-(30\times 25)\\=75$

Thus, the covariance is 75.

Compute the variance of X and Y as follows:

$V(X)=n\cdot\sum X^{2}-(\sum X)^{2}\\=(5\times 226)-(30)^{2}\\=230\\\\V(Y)=n\cdot\sum Y^{2}-(\sum Y)^{2}\\=(5\times 135)-(25)^{2}\\=50$

Compute the correlation coefficient as follows:

$r(X, Y)=\frac{Cov(X, Y)}{\sqrt{V(X)\cdot V(Y)}}$

$=\frac{75}{\sqrt{230\times 50}}$

$=0.69937\\\approx0.70$

Thus, the Pearson's coefficient of correlation between the is 0.700.

5 0

3 years ago

Add the numbers from 1 to 100 by following the same steps you used in 1.

oksano4ka [1.4K]

Summaation of a sequence

or see a smaller scale
from 1 to 10
notice
1+10=11
2+9=11
etc
5+6=11
10/2=5
there are 5 pairs
5*11=55

so

1 to 100
1+100=101
2+99=101
...
50+51=101

100/2=50
there ar 50 pairs
50 times 101=5050

the sum is 5050

3 0

3 years ago