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valkas [14]
3 years ago
10

In Triangle EFG,9 = 12 inches, e = 55 inches and Angle F=75º. Find the area of Triangle EFG, to the

Mathematics
1 answer:
Tresset [83]3 years ago
8 0

9514 1404 393

Answer:

  319 in²

Step-by-step explanation:

The applicable area formula is ...

  A = 1/2(g)(e)·sin(F)

  A = 1/2·(12 in)(55 in)sin(75°) ≈ 319 in²

The area of the triangle is about 319 square inches.

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3 years ago
Find the remaining trigonometric functions of θ based on the given information.csc θ = 257 and cos θ < 0
katrin [286]
Cos(<span>θ) < 0, so we know it would be in Quadrant 2 or 3
then csc(</span>θ) = 257, but csc(θ) = \frac{1}{sin(θ)} = 257
==> sin(<span>θ) = \frac{1}{257}
it is positive, so now we can determine that is in Quadrant 2

sin(</span>θ) = opp./hyp both of opp and hyp are positive but adj suppose to negative because that way it leads the cos(<span>θ) < 0
</span>cos(<span>θ) = adj/hyp
</span>Pythereom to find the adj: 257^{2} -  1^{2}  = adj ==\ \textgreater \  adj  \sqrt{ 257^{2} -   1^{2} } ==\ \textgreater \  adj = 16 \sqrt{258}

cosθ = \frac{16 \sqrt{258} }{257} &#10;
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cos<span>θ = </span>16 \sqrt{258}
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3 years ago
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