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valkas [14]
3 years ago
10

In Triangle EFG,9 = 12 inches, e = 55 inches and Angle F=75º. Find the area of Triangle EFG, to the

Mathematics
1 answer:
Tresset [83]3 years ago
8 0

9514 1404 393

Answer:

  319 in²

Step-by-step explanation:

The applicable area formula is ...

  A = 1/2(g)(e)·sin(F)

  A = 1/2·(12 in)(55 in)sin(75°) ≈ 319 in²

The area of the triangle is about 319 square inches.

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Why do we square the residuals when using the least-squares line method to find the line of best fit? a.) Squaring the residuals
denpristay [2]

Answer:

I would say D

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
Write the linear function f with the values f(1) = 1 and f(-3) = 17. (Note: Use f(x) instead of y.) Show work to get full credit
Ilya [14]

Given:

f(1) = 1 and f(-3) = 17

To find:

The lines function f.

Solution:

If f(a) = b, it means the function f passes through (a,b).

Here, f(1) = 1, it means the function f passes through (1,1).

f(-3) = 17, it means the function f passes through (-3,17).

If a linear function passes through two point (x_1,y_1)\text{ and }(x_2,y_2), then the equation of line is

y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)

The linear function f passes through (1,1) amd (-3,17). So, the equation of linear function is

y-1=\dfrac{17-1}{-3-1}(x-1)

y-1=\dfrac{16}{-4}(x-1)

y-1=-4(x-1)

y-1=-4x+4

Add 1 on both sides.

y-1+1=-4x+4+1

y=-4x+5

Put y=f(x), to write in function notation.

f(x)=-4x+5

Therefore, required lines function is f(x)=-4x+5.

4 0
2 years ago
Which statement is true regarding the graphed functions?
algol13

Answer:

x--5-4-3-2-1

Step-by-step explanation:

because it is x axis not y axis

8 0
2 years ago
Algebra 1 CR-8
antiseptic1488 [7]

\mathrm{Domain\:of\:}\:x^2+2x-15\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:

\mathrm{Range\:of\:}x^2+2x-15:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\ge \:-16\:\\ \:\mathrm{Interval\:Notation:}&\:[-16,\:\infty \:)\end{bmatrix}

\mathrm{Axis\:interception\:points\:of}\:x^2+2x-15:\quad \mathrm{X\:Intercepts}:\:\left(3,\:0\right),\:\left(-5,\:0\right),\:\mathrm{Y\:Intercepts}:\:\left(0,\:-15\right)

\mathrm{Vertex\:of}\:x^2+2x-15:\quad \mathrm{Minimum}\space\left(-1,\:-16\right)

4 0
2 years ago
Please help! Find the equation of the line (graph provided in attached picture) Use exact numbers. y =_ x+_ ( _ represent blanks
Dennis_Churaev [7]

Answer:

y = \frac{3}{4}x - 2

Step-by-step explanation:

Equation of a line is given as y = mx + b

Where,

m = slope of the line = \frac{y_2 - y_1}{x_2 - x_1}

b = y-intercept, which is the value at the point where the line intercepts the y-axis. At this point, x = 0.

Let's find m and b to derive the equation for the line.

m = \frac{y_2 - y_1}{x_2 - x_1}

Use the coordinate pair of any two points on the line. Let's use the following,

(0, -2) = (x_1, y_1) => on the line, when x = 0, y = -2

(4, 1) = (x_2, y_2) => on the line, when x = 4, y = 1

Plug in the values and solve for m

m = \frac{1 - (-2)}{4 - 0}

m = \frac{1 + 2}{4}

m = \frac{3}{4}

b = -2 (the line intercepts the y-axis at this point)

Our equation would be =>

y = mx + b

y = \frac{3}{4}x + (-2)

y = \frac{3}{4}x - 2

5 0
3 years ago
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