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3 years ago

X2 + 1+ x – 2 what is the answer

Mathematics

2 answers:

Vika [28.1K]3 years ago

6 0

It depends on what x is equal to. For example, if x = 3, your equation is 3 * 2 + 1 + 3 - 2 = 8.

Pani-rosa [81]3 years ago

5 0

Add like terms. X2 which is 2 times x. And 1 minus 2.

3x+1-2
3x-1

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PLEASE HELP OR IM GET F

miss Akunina [59]

(8+15+8+3+12)/2+1=24th number will be median

So median is gonna be 21

8 0

2 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=2a%20%7B%20%7D%5E%7B2%7D%20b%20%7B%7D%5E%7B2%7D%20-%207ab%20-%2030" id="TexFormula1" title="2a

yarga [219]

Answer:

(ab - 6)(2ab + 5)

Step-by-step explanation:

Assuming you require the expression factorised.

2a²b² - 7ab - 30

Consider the factors of the product of the coefficient of the a²b² term and the constant term which sum to give the coefficient of the ab- term

product = 2 × - 30 = - 60 and sum = - 7

The factors are - 12 and + 5

Use these factors to split the ab- term

= 2a²b² - 12ab + 5ab - 30 ( factor the first/second and third/fourth terms )

= 2ab(ab - 6) + 5(ab - 6) ← factor out (ab - 6) from each term

= (ab - 6)(2ab + 5) ← in factored form

5 0

3 years ago

Find the product of<br> 2x^2(x + 3)

KengaRu [80]

Answer:

16x

Step-by-step explanation:

2x^2(x+3)

2 times 2 = 4

4x(x+3)

4x + 12x =

16x

5 0

3 years ago

What is the range of the equation

a_sh-v [17]

The range of the equation is $y>2$

Explanation:

The given equation is $y=2(4)^{x+3}+2$

We need to determine the range of the equation.

<u>Range:</u>

The range of the function is the set of all dependent y - values for which the function is well defined.

Let us simplify the equation.

Thus, we have;

$y=2 \cdot 4^{x+3}+2$

This can be written as $y=2^{1+2(x+3)}+2$

Now, we shall determine the range.

Let us interchange the variables x and y.

Thus, we have;

$x=2^{1+2(y+3)}+2$

Solving for y, we get;

$x-2=2^{1+2(y+3)}$

Applying the log rule, if f(x) = g(x) then $\ln (f(x))=\ln (g(x))$ , then, we get;

$\ln \left(2^{1+2(y+3)}\right)=\ln (x-2)$

Simplifying, we get;

$(1+2(y+3)) \ln (2)=\ln (x-2)$

Dividing both sides by $\ln (2)$ , we have;

$2 y+7=\frac{\ln (x-2)}{\ln (2)}$

Subtracting 7 from both sides of the equation, we have;

$2 y=\frac{\ln (x-2)}{\ln (2)}-7$

Dividing both sides by 2, we get;

$y=\frac{\ln (x-2)-7 \ln (2)}{2 \ln (2)}$

Let us find the positive values for logs.

Thus, we have,;

$x-2>0$

$x>2$

The function domain is $x>2$

By combining the intervals, the range becomes $y>2$

Hence, the range of the equation is $y>2$

7 0

3 years ago

A rectangular pool contains 920 cubic meters of water. the pool is .4 meter deep and 100 meters wide. How long is the pool?

LekaFEV [45]

Hi there,

Sol:
Length of the swimming pool = 260 m
Breadth of the swimming pool = 140 m

Let the height of the water in the swimming pool after pouring water be h meters.

Volume of the water poured = 54600 m3

l x b x h = 54600
260 x 140 x h = 54600
h = (54600) / (260 x 140)
h = 1.5 m = 150 cm

Hope it helps

5 0

3 years ago