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Deffense [45]
3 years ago
9

Solve the inequality: 12p + 7 > 139

Mathematics
2 answers:
natima [27]3 years ago
8 0
12p+ 7 > 139
⇒ 12p > 139 -7
⇒ 12p > 132
⇒ p > 132/12
⇒ p > 11

Final answer: p > 11~
8_murik_8 [283]3 years ago
4 0
If you would like to solve the inequality 12 * p + 7 > 139, you can do this using the following steps:

12 * p + 7 > 139
12 * p > 139 - 7
12 * p > 132       /12
p > 132/12
p > 11

The correct result would be p > 11.
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Find the area of the shape shown below.
cricket20 [7]

Answer:

18

Step-by-step explanation:

3+9=12

12/2=6

6x3=18

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3 years ago
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An 8th grade class project involves decorating a rectangular box with the following dimensions.
Margarita [4]

Answer:1500

Step-by-step explanation: so i got the anwser 1539.2 and just rounded to the nearest hundredth which is 1500 hopefully it helps!

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3 years ago
a triangle has an area of 54 m2 and a height of 9m how long is the base of the triangle entered your answer in the box
Delvig [45]
Answer:
base of the triangle = 12 m

Explanation:
Area of the triangle = 1/2 * base * height
We are given that:
area = 54 m^2
height = 9 m

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Area of the triangle = 1/2 * base * height
54 = 1/2 * base * 9
108 = 9*base
base = 12 m

Hope this helps :)
7 0
3 years ago
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Brayden, Howard, and Vincent are on the football team. During a game, Brayden gains 1 less than 5 times the average number of ya
Gnoma [55]

Answer:  If two pair is parallel then it has no solution.

Step-by-step explanation:

Since we have given that

Let the number of gained yards by each player be y

For the case of Brayden:

Equation will be

y=5x-1\\\\y-5x=-1

For the case of Howard :

Equation will be

y=5x+1\\\\y-5x=1

For the case of Vincent :

y=4x+5\\\\y-4x=5

Since First two equations are parallel so it has no solution.

Reason:

y-5x=1\\\\y-5x=-1\\\\\frac{a_1}{a_2}=\frac{b_1}{b_2}=\frac{c_1}{c_2}\\\\\frac{1}{1}=\frac{5}{5}\neq \frac{1}{-1}

Hence, if two pair is parallel then it has no solution.


8 0
3 years ago
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Each person in a group of college students was identified by graduating year and asked when he or she preferred taking classes:
swat32

Answer:

<em>0.615</em>

Step-by-step explanation:

The frequency table is attached below.

We have to calculate, the probability that the student preferred morning classes given he or she is a junior.

i.e P(\text{Morning }|\text{ Junior})

We know that,

P(A\ |\ B)=\dfrac{P(A\ \cap\ B)}{P(B)}

So,

P(\text{Morning }|\text{ Junior})=\dfrac{P(\text{Morning }\cap \text{ Junior})}{P(\text{Junior})}

Putting the values from the table,

\dfrac{P(\text{Morning }\cap \text{ Junior})}{P(\text{Junior})}=\dfrac{\frac{16}{143}}{\frac{26}{143}}=\dfrac{16}{26}=0.615

3 0
3 years ago
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