The length and width of the rug is 20 and 11 feet respectively
The given parameters;
dimension of the room = 19 ft by 28 ft
maximum area of rug she can afford = 220 ft²
For a uniform stripe of floor around the rug, then suppose the uniform excess length of the floor to removed from each dimension = y
(28-2x)(19-2x)=220
532-94x+4x^2=220
4x^2-94x+312=0
x=39/2,4
For x=39/2, dimensions are negative.
The uniform dimension of the floor to be covered by the maximum area of rug she can afford = (28 - 4×2) and (19 -2×4 ) = 20 and 11
Thus, the dimensions of the rug should be 20 feet and 11 feet
- The area of a rectangle is length times breadth.
- Area is the total squares cm occupied by a closed figure.
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Answer:
CU = 117
Step-by-step explanation:
Since the triangles are similar then the ratios of corresponding sides are equal, that is
= 
substituting in values to the ratios
=
( cross- multiply )
24(36x - 1) = 3432 ( divide both sides by 24 )
36x - 1 = 143 ( add 1 to both sides )
36x = 144 ( divide both sides by 36 )
x = 4
CU = 36x - 1 - 26 = (36 × 4) - 27 = 144 - 27 = 117
0.9<span>% of </span>603<span> = 5.43
so estimated is 5.40</span>
Answer:
Her answer is not reasonable. Her average is 83.
Step-by-step explanation:
Add all of her test grades together (96+82+78+76=332)
To find the average, you need to add all test grades she got and then divide the sum by the total number of numbers added (in this case, we added 4 tests together, so we need to divide by 4)

So she added wrong and forgot to divide by the total number of tests.
I think the answer is 120.
(Hope this helps ;3)