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Answer:
11.67
Step-by-step explanation:
Answer:
Step-by-step explanation:
Represent the length of one side of the base be s and the height by h. Then the volume of the box is V = s^2*h; this is to be maximized.
The constraints are as follows: 2s + h = 114 in. Solving for h, we get 114 - 2s = h.
Substituting 114 - 2s for h in the volume formula, we obtain:
V = s^2*(114 - 2s), or V = 114s^2 - 2s^3, or V = 2*(s^2)(57 - s)
This is to be maximized. To accomplish this, find the first derivative of this formula for V, set the result equal to 0 and solve for s:
dV
----- = 2[(s^2)(-1) + (57 - s)(2s)] = 0 = 2s^2(-1) + 114s - 2s^2
ds
Simplifying this, we get dV/ds = -4s^2 + 114s = 0. Then either s = 28.5 or s = 0.
Then the area of the base is 28.5^2 in^2 and the height is 114 - 2(28.5) = 57 in
and the volume is V = s^2(h) = 46,298.25 in^3
Answer:
With $30, Peter can afford 5 hours
Step-by-step explanation:
Given
Insurance Charge = $7.5
Charges = $4.5 per hour
Required
Determine the number of hours $30 can afford
First, we need to determine the equation.
<em>Total Charges = Charges per hour + Insurance Charge</em>
Substitute values for Charges per hour and Insurance Charge
Total Charges = 4.5 per hour + 7.5
Let the number of hours be n;
So,
Total Charges = 4.5n + 7.5
To calculate Peter's; substitute 30 for total charges
Subtract 7.5 from both sides
Divide both sides by 4.5
Hence;
<em>With $30, Peter can afford 5 hours</em>
Answer:
20%
Step-by-step explanation:
