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vredina [299]
3 years ago
11

Which of the following measuring instruments is used to test the quality of wire insulation?

Mathematics
1 answer:
disa [49]3 years ago
6 0
The answer to this question is : <span>Megohm meter</span>
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PLZ HELP! 20 POINTS!!
ivann1987 [24]
Given list of values
A = {23, 34, 19, 10, 9, 20, 40, 43, 28, 29, 36, 13, 27, 23, 36, 37, 7}

Sort list A to get list B
B = {7, 9, 10, 13, 19, 20, 23, 23, 27, 28, 29, 34, 36, 36, 37, 40, 43}

The smallest value is 7, so the min is 7
The largest value is 43, so the max is 43

Look through list B to find the middle-most value. What you can do is cross off each pair of outer values (see figure 1 in the attached images) until you are left with the middle value
Or you can note how there are 17 values so the median is at slot 9 (there are 8 values below the median; 8 values above the median; the 8 is from 17/2 = 8.5)

Once you know the median is 27, we split the list B into two parts
The first part, we'll call it L for lower half is
L = {7, 9, 10, 13, 19, 20, 23, 23}
which is the list of all values lower or smaller than the median.
The median of list L is 16 because its the midway point between 13 and 19. We can compute (13+19)/2 = 32/2 = 16. This is the value of Q1

The upper half U is
U = {28, 29, 34, 36, 36, 37, 40, 43}
this list shows all the values larger than the median.
The value of Q3 is 36. We find the midpoint of 36 and 36 which is just 36.
The value of Q3 is the same as the median of list U

------------------------------------------------

Five Number Summary:
Min = 7
Q1 = 16
Median = 27
Q3 = 36
Max = 43

This five number summary is then used to construct the box-and-whisker plot. See figure 2 in the attached images. The diagram shows how each piece of the boxplot is put together (eg: the left edge of the box is the value of Q1). 

5 0
3 years ago
Which of the following displays cannot be used to compare data from two different sets?
Alex73 [517]

Answer:

Scatter plot charts are good for relationships and distributions, but pie charts should be used only for simple compositions — never for comparisons or distributions.

8 0
3 years ago
a family has two cars. the first car has a fuel efficiency of 20 miles per gallon of gas and the second has a fuel efficiency of
Kryger [21]
Let the number of gallons consumed be the first car be x, and that of the second car, y. Then:
x + y = 50 . . . . . . . (1)
20x + 15y = 850. . . (2)

(1) x 20 => 20x + 20y = 1000 . . . (3)
(2) - (3) => -5y = -150 => y = -150/-5 = 30

From (1), x + 30 = 50 => x = 50 - 30 = 20

Therefore, first car consumed 20 gallons and the second consumed 30 gallons.
3 0
3 years ago
Hey can you please help me posted picture of question
Ronch [10]
The formulas for conditional probability are:
P(A\cap B')=P(A)\cdot P(B'|A)
P(A\cap B')=P(B')\cdot P(A|B').
Since P(A\cap B')= \frac{1}{6} and p(B')= \frac{7}{18}, you have the equation \frac{1}{6} = \frac{7}{18} \cdot P(A|B').
Therefore, P(A|B')= \frac{1}{6} : \frac{7}{18} =\frac{1}{6} \cdot \frac{18}{7} = \frac{3}{7}.
Answer: The correct choice is D.


8 0
3 years ago
18x + 7, when x = 2<br><br><br><br><br><br>​
Ganezh [65]

Answer:

43

Step-by-step explanation:

18x+7

=18×2+7

=36×9

=45

6 0
3 years ago
Read 2 more answers
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