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3 years ago

8

Reduce to lowest terms 4x^3y^4/-8xy^2

1 answer:

Lerok [7]3 years ago

5 0

= (4x^3y^4)/(-8xy^2)
simplify exponents by subtracting the denominator exponent from numerator exponent [x^(3-1)]

= (4x^3y^4)/(-8xy^2)
simplify -4/8 by 4 into numerator and denominator

= (-1x^2y^2)/2

= (-x^2y^2)/2

ANSWER: (-x^2y^2)/2

Hope this helps! :)

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Answer:

d) P(D|E)

Step-by-step explanation:

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D = person on a diet

Given the expression :

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This simply refers to a conditional probability whereby the subset from which the probability that a randomly chosen person is on diet is to be calculated is the subset of those who exercise.

In statistical parlance, the statement is expressed as ; the probability of A given B = P(A|B)

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2 years ago

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A simple random sample of size n=14 is obtained from a population with μ=64 and σ=19.

madam [21]

Answer:

a) A. The population must be normally distributed

b) P(X < 68.2) = 0.7967

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Step-by-step explanation:

a) The population is normally distributed having a mean ( $\mu_x$ ) = 64 and a standard deviation ( $\sigma_x$ ) = $\frac{19}{\sqrt{14} }$

b) P(X < 68.2)

First me need to calculate the z score (z). This is given by the equation:

$z=\frac{x-\mu_x}{\sigma_x}$ but μ=64 and σ=19 and n=14, $\mu_x=\mu=64$ and $\sigma_x=\frac{ \sigma}{\sqrt{n} }=\frac{19}{\sqrt{14} }$

Therefore: $z=\frac{68.2-64}{\frac{19}{\sqrt{14} } }=0.83$

From z table, P(X < 68.2) = P(z < 0.83) = 0.7967

P(X < 68.2) = 0.7967

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First me need to calculate the z score (z). This is given by the equation:

$z=\frac{x-\mu_x}{\sigma_x}$

Therefore: $z=\frac{65.6-64}{\frac{19}{\sqrt{14} } }=0.32$

From z table, P(X ≥ 65.6) = P(z ≥ 0.32) = 1 - P(z < 0.32) = 1 - 0.6255 = 0.3745

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3 years ago

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emmasim [6.3K]

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Step-by-step explanation:

<u>Given </u>

(6 + 5x) + (7x + 3)

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<u>Combine like terms </u>

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Hope this helps!! :)

Please let me know if you have any questions

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3 years ago