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kiruha [24]
3 years ago
15

Round 10,031.464 to the nearest hundred.

Mathematics
1 answer:
insens350 [35]3 years ago
7 0

Answer:

10,031.46

Rounded to the nearest 0.01 or

the Hundredths Place.

Step-by-step explanation:

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John is building a rectanglular parking lot. The area of the lot is A(x) = -2x^2 + 200x.
stealth61 [152]

Answer:

40, 2000, 50

Step-by-step explanation:

I am not sure, but if you find any other answer, you can use this numbers

4 0
3 years ago
From A to B a private plane flies 2.8 hours at 110 mph on a bearing of 64 degrees . It turns at point B and continues another 1.
Firdavs [7]

Answer:

a. 360.323 m

b. 95.265^{o}

Step-by-step explanation:

Distance covered from A to B = speed x time

                                                 = 110 x 2.8

                                                 = 308 m

Distance covered from B to C = speed x time

                                                  = 110 x 1.7

                                                  = 187 m

The sum of angles at B = 64^{o} + 26^{o}

                                       = 90^{o}

a. The distance of the plane from it starting point to C can be determined by applying the cosine rule.

b^{2} = a^{2} + c^{2} - 2ac Cos B

Sot hat;

b^{2} = 187^{2} + 308^{2} - 2(187 x 308) Cos 90^{o}

But, Cos 90^{o} = 0

So that,

b^{2} = 187^{2} + 308^{2}

  = 34969 + 94864

  = 129833

b = \sqrt{129833}

  = 360.323

The distance from A to C is 360.323 m.

b. Applying the sine rule;

\frac{a}{SinA} = \frac{b}{SinB}

\frac{187}{SinA} = \frac{360.323}{Sin90^{o} }

\frac{187}{SinA} = \frac{360.323}{1}

Sin A = \frac{187}{360.323}

         = 0.5190

⇒ A = Sin^{-1} 0.5190

       = 31.265^{o}

The bearing of the plane from its original location = 64^{o} + 31.265^{o}

                                                     = 95.265^{o}

8 0
3 years ago
Which of the following is an arithmetic sequence?
skelet666 [1.2K]
I think it's D, because 3/4 x 2 = - 3/2
and then - 3/2 x - 2 = 3
3 x - 2 = - 6

Hope that helps <3
5 0
3 years ago
Graph the image of kite ABCD after a rotation 180° counterclockwise around the origin.
rewona [7]

Solution:

Given a kite ABCD on a graphhh, with the coordinates given below

\begin{gathered} A(-8,-6) \\ B(-7,-2) \\ C(-1,-6) \\ D(-7,-10) \end{gathered}

If the kite is rotated 180° counterclockwise around the origin,

The rule for a rotation 180° counterclockwise around the origin is

(x,y)\rightarrow(-x,-y)

The coordinates of the kite after the rotation of 180° counterclockwise around the origin will be

\begin{gathered} A(-8,-6)\rightarrow A^{\prime}(8,6) \\ B^{\prime}(-7,-2)\rightarrow B^{\prime}^(7,2) \\ C(-1,-6)\rightarrow C^{\prime}(1,6) \\ D(-7,-10)\rightarrow D^{\prime}(7,10) \end{gathered}

The graph is shown below

5 0
1 year ago
What is the answer for -11x-11
Llana [10]

Answer:

-11(x+1)

Step-by-step explanation:

nice picture!

6 0
3 years ago
Read 2 more answers
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