The probability that no one in the family of 4 will be hospitalized during a year is 0.52
Step-by-step explanation:
The probability for a person to be hospitalized during one year is
As a consequence, the probability for a person of NOT being hospitalized during one year is
If we have 4 people in the family, the probability of each of them of NOT being hospitalized during the year is independent from the probability of the others - therefore, these are independent events. This means that the total probability of the 4 people of not being hospitalized during a year is:
So, the probability that no one in the family of 4 will be hospitalized during a year is 0.52.
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Divide the first equation by 2 and add the result to the second equation. This will eliminate x.
... (-4x -2y)/2 + (2x +4y) = (-12)/2 +(-12)
... 3y = -18 . . . . . collect terms
... y = -6 . . . . . . . divide by 3
Substitute this into either equation to find x. Let's use the second equation, where the coefficient of x is positive.
... 2x +4(-6) = -12
... 2x = 12 . . . . . . . . add 24
... x = 6 . . . . . . . . . . divide by 2
The solution is (x, y) = (6, -6).
Answer:
y = 60, x= 50
Step-by-step explanation:
y + 120 = 180
subtract 120 from both sides
y = 60
60 + 70 = 130
x + 130 = 180
subtract 130 from both sides
x = 50
We can't see the graph so we don't know the question
Answer:
x=2
Step-by-step explanation:
y=-7x+13
y=-1
plug in -1 for y in the first problem.
-1=-7x+13
subtract 13 by both sides
-14=-7x
divide both sides by -7 to isolate x
2=x
hope that helped have a good day
