(4x+4)(6x+6) the sum

In a binomial distribution, n = 8 and π=0.36. Find the probabilities of the following events. (Round your answers to 4 decimal p

skelet666 [1.2K]

Answer:

$\mathbf{P(X=5) =0.0888}$

P(x ≤ 5 ) = 0.9707

P ( x ≥ 6) = 0.0293

Step-by-step explanation:

The probability of a binomial mass distribution can be expressed with the formula:

$\mathtt{P(X=x) =(^{n}_{x} ) \ \pi^x \ (1-\pi)^{n-x}}$

$\mathtt{P(X=x) =(\dfrac{n!}{x!(n-x)!} ) \ \pi^x \ (1-\pi)^{n-x}}$

where;

n = 8 and π = 0.36

For x = 5

The probability $\mathtt{P(X=5) =(\dfrac{8!}{5!(8-5)!} ) \ 0.36^5 \ (1-0.36)^{8-5}}$

$\mathtt{P(X=5) =(\dfrac{8!}{5!(3)!} ) \ 0.36^5 \ (0.64)^{3}}$

$\mathtt{P(X=5) =(\dfrac{8 \times 7 \times 6 \times 5!}{5!(3)!} ) \times \ 0.0060466 \ \times 0.262144}$

$\mathtt{P(X=5) =(\dfrac{8 \times 7 \times 6 }{3 \times 2 \times 1} ) \times \ 0.0060466 \ \times 0.262144}$

$\mathtt{P(X=5) =({8 \times 7 } ) \times \ 0.0060466 \ \times 0.262144}$

$\mathtt{P(X=5) =0.0887645}$

$\mathbf{P(X=5) =0.0888}$ to 4 decimal places

b. x ≤ 5

The probability of P ( x ≤ 5) $\mathtt{P(x \leq 5) = P(x = 0)+ P(x = 1)+ P(x = 2)+ P(x = 3)+ P(x = 4)+ P(x = 5})$

${P(x \leq 5) = ( \dfrac{8!}{0!(8!)} \times (0.36)^0 \times (1-0.36)^8 \ ) + \dfrac{8!}{1!(7!)} \times (0.36)^1 \times (1-0.36)^7 \ +$ $\dfrac{8!}{2!(6!)} \times (0.36)^2 \times (1-0.36)^6 \ + \dfrac{8!}{3!(5!)} \times (0.36)^3 \times (1-0.36)^5 + \dfrac{8!}{4!(4!)} \times (0.36)^4 \times (1-0.36)^4 \ + \dfrac{8!}{5!(3!)} \times (0.36)^5 \times (1-0.36)^3 \ )$

P(x ≤ 5 ) = 0.0281+0.1267+0.2494+0.2805+0.1972+0.0888

P(x ≤ 5 ) = 0.9707

c. x ≥ 6

The probability of P ( x ≥ 6) = 1 - P( x ≤ 5 )

P ( x ≥ 6) = 1 - 0.9707

P ( x ≥ 6) = 0.0293

4 0

2 years ago

To estimate the difference we need four averages for the categorized groups i.e., control group before change, control group aft

nataly862011 [7]

Answer:

b. False

Step-by-step explanation:

In a research study, when a researcher wants to find the impact of a new treatment, then the researcher randomly divides the the study participants into two groups. The groups are :

-- control group

-- treatment group

The control group is a group that is used to establish the cause-and-effect relationship by making the effect of an independent variable isolate. It receives no treatment or some standard treatment for the which the effect is already known.

The treatment group receives the treatment for which the effect the researcher is interested in.

Thus the averages of the four categorized groups are not required for estimating the difference.

Therefore, the answer is FALSE.

3 0

2 years ago

In the graph below, the hyperbola gets close to the red lines but never touches

soldier1979 [14.2K]

Answer:

Option A asymptote.

Step-by-step explanation:

Asymptotes are lines to which the graph approaches very it can come very close to it but will never touch it. Asymptote are the limits of a graph.

IN the given graph of Hyperbola the two blue lines representing the Hyperbola are coming too close to the red lines but not touching it .

The two red lines are called the Asymptotoes of the Hyprbola.It is the limit of the Hyperbola.

Step-by-step explanation:

7 0

2 years ago

Sierra drives for h hours at a rate of 2x miles per hour. Which expression shows the distance that she drives after h hours

Eva8 [605]

Answer:

Distance traveled by Sierra in h hours at a rate of 2x miles per hour = 2xh

Explanation:

Distance traveled by a body = Velocity of the body * Time taken by the body

Here velocity of Sierra = 2x miles per hour

Time taken by Sierra = h hours.

Distance traveled by Sierra = 2x * h = 2xh

So distance traveled by Sierra in h hours at a rate of 2x miles per hour = 2xh

8 0

2 years ago

Emily's family loves to work together in the garden.They have a slight preference for flowers, as 60\%60%60, percent of their pl

mylen [45]

50 plants total, 40% are vegetables

40% = 40/100 = 0.40

40% of 50 = 0.40*50 = 20

<h3>Answer: There are 20 vegetable plants</h3>

5 0

3 years ago