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S_A_V [24]
3 years ago
6

Find all polar coordinates of point P where P = ordered pair 6 comma negative pi divided by 5.

Mathematics
2 answers:
Rudik [331]3 years ago
8 0

Answer:

All polar coordinates of point P are (6,-\frac{\pi}{5}+2n\pi) and (-6,-\frac{\pi}{5}+(2n+1)\pi), where n is an integer.

Step-by-step explanation:

The given point is

P=(6,-\frac{\pi}{5})

If a point is P=(r,\theta), then all polar coordinates of point P are defined as

(r,\theta)=(r,\theta+2n\pi)

(r,\theta)=(-r,\theta-(2n+1)\pi)

where n is an integer.

In the given point r=6 and \theta=-\frac{\pi}{5}. So all polar coordinates of point P are defined as

(6,-\frac{\pi}{5})=(6,-\frac{\pi}{5}+2n\pi)

(6,-\frac{\pi}{5})=(-6,-\frac{\pi}{5}+(2n+1)\pi)

Therefore all polar coordinates of point P are (6,-\frac{\pi}{5}+2n\pi) and (-6,-\frac{\pi}{5}+(2n+1)\pi), where n is an integer.

Allushta [10]3 years ago
6 0

Answer:

P(6,-π/6) = (6, -π/6 + 2nπ) and P(-6,-π/6) = (-6, -π/6 + (2n+1)π)

Step-by-step explanation:

We need to find all polar coordinates of

P = (6,\frac{-\pi }{6})

The polar coordinates of any point can be reresented by (r,Ф)

where

(r,Ф) = (r, Ф+2nπ) where n is any integer and r is positive

and

(r,Ф) = (-r, Ф+(2n+1)π) where n is any integer and r is negative.

So, in the question given, r = 6 and Ф = -π/6

So, Polar coordinates will be:

P(6,-π/6) = (6, -π/6 + 2nπ) where where n is any integer and r is positive

and

P(-6,-π/6) = (-6, -π/6 + (2n+1)π) where n is any integer and r is negative.

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