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Ksivusya [100]
2 years ago
6

Solve.

Mathematics
1 answer:
Furkat [3]2 years ago
3 0

Answer:

-0.03

Step-by-step explanation:

-59x+3.2=5

-59x=5-3.2

-59x=1.8

x=1.8/-59

x=-0.03

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iVinArrow [24]

Answer:

Since Tracy is charged $29 for 250 free minutes so:

For x ≤ 250, f(x) = $29

tracy is charged an extra $0.35 per minute for calls over 250 minutes, so:

For x ≥ 250, f(x) = 29 + 0.35(x - 250)

7 0
3 years ago
Help please question in picture
german

Answer:

220

Step-by-step explanation:

Area of square=8*20=160

Area of triangle=(6*20)/2=60

160+60

8 0
3 years ago
Read 2 more answers
A single letter from the word zookeeper is chosen. What is the probability of choosing k or an e? Express your answer as a fract
Westkost [7]

Answer:

4/9

Step-by-step explanation:

There are 9 letters in the word zookeeper.  4 of those letters are either a k or an e.  So the probability is 4/9.

4 0
3 years ago
What is the equation for the translation of X^2+y^2=9 four units to the right and three units down
icang [17]
We know that
X²+y²=9 -------> X²+y²=3²
is the equation of a circle with center (0,0) and radius r=3 units
so
<span>the translation of four units to the right and three units down is equals to move the center (0,0)--------> (0+4,0-3)------> (4.-3)

the new center of the circle is (4,-3)
the new equation is
(x-4)</span>²+(y+3)²=3²

see the attached figure

4 0
4 years ago
Lee spent $36 to purchase a combination of drinks, sandwiches, and chips for himself and his friends. A drink costs $2, a sandwi
valkas [14]

2x+4y+0.50z=36 represents the situation.

Step-by-step explanation:

Let,

Drinks = x

Sandwich = y

And,

Chips = z

Total amount on these items = $36

According to the statement;

x(cost\ of\ one\ drink)+y(cost\ of\ one\ sandwich)+z(cost\ of\ one\ chips)=\ Total\ amount\ spent\\2x+4y+0.50z=36

2x+4y+0.50z=36 represents the situation.

Keywords: Linear equations

Learn more about linear equations at:

  • brainly.com/question/10081622
  • brainly.com/question/10341324

#LearnwithBrainly

7 0
3 years ago
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