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3 years ago

8

Help please! Under 5 mins

1 answer:

Inga [223]3 years ago

8 0

Answer:

2.3

Step-by-step explanation:

Using SOH CAH TOA, we can label CB as the alternate side seeing as it's opposite to the known angle 50 degrees. We know AB is the hypotenuse since it's the longest side. Therefore CA must be the alternate side.

Since we want to know BC, and we know information about AB, we need to use the use of the hypotenuse and the opposite. In SOH CAH TOA, SOH uses both of these.

Using S O H, we understand that sin(50) * 3 = CB

Therefore CB = 2.3 to 1 decimal place.

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The partial pressure of carbon dioxide in a mixture is 0.31 atm.

juin [17]

Answer:

$P_{Co2}= X_{Co2} P_{tot}$

Where $P_{tot}$ represent the total pressure and $X_{Co2}$ the fraction of carbon dioxide is 0.46 and we can find the total pressure with this formula:

$P_{tot}= \frac{P_{Co2}}{X_{Co2}}$

And replacing we got:

$P_{tot}= \frac{0.31 atm}{0.46}= 0.674 atm$

Step-by-step explanation:

For this case the partial presure of carbon dioxide is given by:

$P_{Co2}= X_{Co2} P_{tot}$

Where $P_{tot}$ represent the total pressure and $x_{Co2}$ the fraction of carbon dioxide is 0.46 and we can find the total pressure with this formula:

$P_{tot}= \frac{P_{Co2}}{X_{Co2}}$

And replacing we got:

$P_{tot}= \frac{0.31 atm}{0.46}= 0.674 atm$

4 0

3 years ago

40 tens.how many hundreds

Sladkaya [172]

400. Just add a zero when you're dealing with tens

7 0

3 years ago

Michael has a set of 24 math problems to do for homework. Michael completed 1/4 of his homework in 3/4 of an hour. If he continu

gtnhenbr [62]

Given:

Total number of problems = 24

Michael completed $\dfrac{1}{4}$ of his homework in $\dfrac{3}{4}$ of an hour.

To find:

What fraction of his homework would he complete in one hour.

Solution:

We have,

Part of work done in $\dfrac{3}{4}$ of an hour $=\dfrac{1}{4}$

Part of work done in an hour $=\dfrac{4}{3}\times \dfrac{1}{4}$

$=\dfrac{1}{3}$

Therefore, he complete $\dfrac{1}{3}$ of his homework in 1 hour. Hence, all options are incorrect.

3 0

3 years ago

Maria had planned to walk 10 1/8 miles on wednesday, if she walked 7 2/8 miles in the morning how far would she need to walk in

Ugo [173]

Answer:

Distance Maria had to walk in the afternoon is $2\frac{7}{8}$

Step-by-step explanation:

Lets take that Maria walked $x$ miles in the afternoon.

Distance walked in the morning + distance walked in the afternoon = $10\frac{1}{8}$

⇒ $7\frac{2}{8} +x=10\frac{1}{8}$

$\frac{58}{8} +\frac{8x}{8} =\frac{81}{8}$

$\frac{58+8x}{8} =\frac{81}{8}$

$58+8x=81$

$8x=81-58\\$

$8x=23$

$x=\frac{23}{8}$

$x=2\frac{7}{8}$

7 0

3 years ago

Simplify 12/5(10/3b+15/4) .

Elodia [21]

Step 1. Simplify 10/3b to 10b/3
12/5(10b/3 + 15/4)
Step 2. Distribute
8b + 9

7 0

3 years ago

Read 2 more answers