Answer:
The rectangle has a width of 4 and a height of 8
Step-by-step explanation:
Let the height of the rectangle be H and the width be W.
We know the height of the rectangle is twice the width, so:
H = 2W
The area of a rectangle, A, is given by A = W * H, so in this case:
32 = W * 2W
32 = 2W²
W² = 16
W = 4
Knowing that the width is 4, the height must be 8. This gives us an area of 32.
the top number is the exponent, the bottom number is the root.
15) ![\sqrt[3]{(2p)^{1} }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%282p%29%5E%7B1%7D%20%7D)
= ![\sqrt[3]{2p}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B2p%7D)
16) ![16\sqrt[4]{(x)^{3} }](https://tex.z-dn.net/?f=16%5Csqrt%5B4%5D%7B%28x%29%5E%7B3%7D%20%7D)
= ![16\sqrt[4]{x^{3} }](https://tex.z-dn.net/?f=16%5Csqrt%5B4%5D%7Bx%5E%7B3%7D%20%7D)
You have to do similar calculations you use in algebra. This is how I get the answer;
First I draw out the algebraic formula 55m • X = 8,484 m (meters) 2 (squared). Then I switch the sign from multiplication to division and switch put numbers 55 and 8,484 in different places and change it to your new formula 8,484/(divided) 55 =X. Then you do the math of 8,484 divided by 55 and get an answer of 154.254545. But you can just leave it at the first 2 digits on the right side of the decimal by rounding 4 down and leaving it at an answer of ~~(<This is your answer after being put together with these tips (you always right your final answer using your formula and plugging in the number that we got from dividing 8,484 by 55;
Final answer ( if they wanted it included in a formula); 8,484/55=X let X=~~154.25
Final answer (if they wanted it as one final number as you answer); ~~154.25
*Hope these tips helped you with this mathematical problem :)
1/7 th chance 0.14%
_____________________________________________________________Redstar215
