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Brums [2.3K]
3 years ago
7

Is this correct yall ??

Mathematics
1 answer:
Katarina [22]3 years ago
8 0

Answer:

What do you need to know?

Step-by-step explanation:

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Ruguru wants to rent a car for 3 days. The cost, C, in dollars, for the rental is shown in the box, where d
olga nikolaevna [1]

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A: $15

Step-by-step explanation:

35·3=105

105+25=135

135-115=15

Hoped this helps!

3 0
9 months ago
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Example of propertional relationship
Leokris [45]

Answer:

1/2 and 6/12 have a proportional relationship, which means they are the same.

Step-by-step explanation:

3 0
2 years ago
Multiply. What is the value of the second partial product 27x108
jeyben [28]
<h2>Answer:</h2><h2>The  partial products of (27) (108) are 216 , 0 , 27.</h2>

Step-by-step explanation:

To find the value of the second partial product 27x108,

Here the multiplicand = 27

The multiplier = 108

The partial products of the multiplication are :

(27) (8)   =  0 2 1 6

(27) (0)   =  0 0 0

(27) (1)    =  2 7

Adding the terms, we get 2916.

The partial products are 216 , 0 , 27.

5 0
3 years ago
Factor completely x2 - 49
siniylev [52]

Answer: (x + 7)(x - 7)

Explanation: If a variable is taken to an even power, that variable is a perfect square. In this case, x² would therefore be a perfect square.

Since 49 is also a perfect square, what we have here is the difference of two squares. That can be factored as the product of two binomials one with a plus in the middle and one with a minus in the middle.

In the first position will be the factors of x² that are the same.

So we have <em>x</em> and <em>x</em>.

In the second position we will have the

factors of 49 that are the same, 7 and 7.

(x + 7)(x - 7) is your answer which is a factored version of x² - 49.

5 0
2 years ago
Read 2 more answers
1) 2a × 2b 2) 3a × 2b × 2a 3) 2a × 4b × b 4) 3b × 2a × b 5) 3a × 2b × 2c 6) 2a × 3b × b × c 7) a × 4b × 2a × 2c 8) 3a × 3b × 3c
podryga [215]

Step-by-step explanation:

1) = 4ab

2) 12a2b

3) 8ab2

4) 6ab2

5) 12abc

6) 6ab2c

7) 16a2bc

8) 27abc

6 0
3 years ago
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