3 years ago

Evaluate ƒ( x ) = x 2 + 1 for ƒ(-1).

Mathematics

2 answers:

Tanya [424]3 years ago

5 0

$If f(x) = x^{2} + 1$
$then f(-1) = (-1)^{2} + 1$
∴ $f(-1) = 2$

Thepotemich [5.8K]3 years ago

3 0

When solving this you get f= 2

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