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3 years ago

SOMEONE PLEASE HELP ME i really need this one

Mathematics

1 answer:

jek_recluse [69]3 years ago

8 0

Answer:

Wait are u trying to find the area of a shape???

Step-by-step explanation:

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Is the function odd, even or neither?

iren2701 [21]

Answer is: even

This function’s graph is symmetric with respect to the y-axis therefore, this function is even.

7 0

3 years ago

Find the probability of obtaining exactly one tail when flipping nine coins. Express your as fraction terms on a rounded the nea

Sveta_85 [38]

Answer:0.017578

Step-by-step explanation:

Given

Nine coins are flipped

So the probability of getting a tail is $\frac{1}{2}$

Because on flipping a coin could either yield Head or tail

so getting a tail on nine trails is $\frac{1}{2^9}$

but this tail can come on first coin or second or third ....

So there are 9 possible ways

So probability of getting a tail on flipping nine coin is $9\times \frac{1}{2^9}$

$=\frac{9}{2^9}=0.017578$

6 0

3 years ago

If getting $1 for every correct answer on this test makes you study harder for the next test, then being given $1 is a form of _

Anastaziya [24]

Hello there,
<span>positive reinforcement is the answer

Hope this helps ^_^

~Top
</span>

5 0

4 years ago

On an exam with μ = 52, you have a score of X = 56. Which of the following values for the standard deviation would give you the

Aleonysh [2.5K]

Answer:

σ = 2 (option a)

Step-by-step explanation:

You would want the smallest standard deviation possible.

Think of it like this: if everyone, other than you, got only 50, 51, 52, 53 then you would be the ultimate highest position in the class.

As opposed to being an average position if the scores were about 49, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60 ---your score would not put you in the highest position in the class distribution.

So, a standard deviation of σ = 2 would give you the highest position in the class distribution.

5 0

2 years ago

Fill the missing values to make the equations true.

taurus [48]

Logarithm properties:

$\displaystyle \log_a b+\log_a c=\log_a (b\cdot c)\\\\\log_ab-\log_a c=\log_a \left( \frac{b}{c} \right)\\\\\log_{a^p}b^q= \frac{q}{p} \log_a b$

According to this, we can get:

$\displaystyle a)\log_7 3+\log_7 8=\log_7 (3\cdot 8)=\log_724\\\\b) \log_89-\log_85=\log_8 \frac{9}{5}\\\\c)\log_325=2\log_35$

3 0

3 years ago