No
Let the groups be x and 2x
Its decimal not natual so can't be divided
Answer:
4*x^4*y^22
Step-by-step explanation:
Your goal here is to REDUCE the given expression to simplest terms.
One way in which to approach this problem would be to rewrite (2x^2y^10)^3 as: (2x^2*y^8)*y^2*(2x^2*y^10)^2.
Dividing this rewritten expression by 2x^2*y^8 results in:
y^2(2x^2*y^10)^2.
We now need to raise (2x^2*y^10) to the power 2. Doing this, we get:
4x^4*y^20.
Multiply this by y^2 (see above):
y^2*4x^4*y^20
The first factor is 4: 4y^2*x^4*y^20. This is followed by the product of y^2 and y^20: 4*y^22*x^4
Finally, this should be re-written as
4*x^4*y^22
Another way of doing this problem would involve expanding the numerator fully and then cancelling out like factors:
8*x^6*y^30 4*x^4*y^22
----------------- = ------------------ = 4*x^4*y^22
2x^2y^8 1
Answer:
out of
Step-by-step explanation:
Answer:
17
Step-by-step explanation:
you said that in the problem lol
Answer:
The axis of symmetry will be at 1
Step-by-step explanation:
The middle of -3 and 5 will be the axis :)
-3, -2, -1, 0, 1, 2, 3, 4, 5
-2, -1, 0, 1, 2, 3, 4
-1, 0, 1, 2, 3
0, 1, 2
1
