The taylor series for the f(x)=8/x centered at the given value of a=-4 is -2+2(x+4)/1!-24/16 
/2!+...........
Given a function f(x)=9/x,a=-4.
We are required to find the taylor series for the function f(x)=8/x centered at the given value of a and a=-4.
The taylor series of a function f(x)=
Where the terms in f prime 
(a) represent the derivatives of x valued at a.
For the given function.f(x)=8/x and a=-4.
So,f(a)=f(-4)=8/(-4)=-2.
(a)=(-4)=-8/(
=-8/16
=-1/2
The series of f(x) is as under:
f(x)=f(-4)+
=-2+2(x+4)/1!-24/16 /2!+...........
Hence the taylor series for the f(x)=8/x centered at the given value of a=-4 is -2+2(x+4)/1!-24/16 /2!+...........
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The slope is 0 because there is no slope it is not pointing up nor is it down. It is just a straight line. I hope this helps!! Have a nice day!!
Answer:
C. 0, -1, 3
Step-by-step explanation:
Note: There is no graph. I assume you mean "zeroes/roots" by "solutions".
x(x^2-2x-3)=0
/(x^2-2x-3)
x=0
x^2-2x-3 = x^2+x-3x-3 = x(x+1) + ( -3(x+1) = (x-3)(x+1)
/(x-3) --> x +1 =0, x=-1
/(x+1) --> x-3 = 0, x=3
Answer:
width = x+2
Step-by-step explanation:
area/length = width
(x^2+9x+14) / (x+7) =?
(x+7)(x+2) / (x+7) = x+2
Answer:
its to long for me
Step-by-step explanation:
