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3 years ago

Easy math true or false?

Mathematics

2 answers:

sergey [27]3 years ago

5 0

Answer:

True

Step-by-step explanation:

It is true because the solutions are x = -4, -3, and 3.

I graphed the equations on the graph below.

If this answer is correct, please make me Brainliest!

Kipish [7]3 years ago

3 0

Answer:

True

Step-by-step explanation:

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A fair six-sided die is rolled 54 times. Theoretically, about how many times should a roll of "3" occur?

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Step-by-step explanation:

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2 years ago

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3 years ago

Five cards are drawn from a standard 52-card playing deck. A gambler has been dealt five cards—two aces, one king, one 3, and on

Nookie1986 [14]

Answer:

The probability that he ends up with a full house is 0.0083.

Step-by-step explanation:

We are given that a gambler has been dealt five cards—two aces, one king, one 3, and one 6. He discards the 3 and the 6 and is dealt two more cards.

We have to find the probability that he ends up with a full house (3 cards of one kind, 2 cards of another kind).

We know that gambler will end up with a full house in two different ways (knowing that he has given two more cards);

If he is given with two kings.
If he is given one king and one ace.

Only in these two situations, he will end up with a full house.

Now, there are three kings and two aces left which means at the time of drawing cards from the deck, the available cards will be 47.

So, the ways in which we can draw two kings from available three kings is given by = $\frac{^{3}C_2 }{^{47}C_2}$ {∵ one king is already there}

= $\frac{3!}{2! \times 1!}\times \frac{2! \times 45!}{47!}$ {∵ $^{n}C_r = \frac{n!}{r! \times (n-r)!}$ }

= $\frac{3}{1081}$ = 0.0028

Similarly, the ways in which one king and one ace can be drawn from available 3 kings and 2 aces is given by = $\frac{^{3}C_1 \times ^{2}C_1 }{^{47}C_2}$

= $\frac{3!}{1! \times 2!}\times \frac{2!}{1! \times 1!} \times \frac{2! \times 45!}{47!}$

= $\frac{6}{1081}$ = 0.0055

Now, probability that he ends up with a full house = $\frac{3}{1081} + \frac{6}{1081}$

= $\frac{9}{1081}$ = <u>0.0083</u>.

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3 years ago

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Quincy bought necklaces for $8.00 each. At what price would he need to sell them to make a 25% profit

Zepler [3.9K]

10 dollars. 8÷4=2. 8+2=10

25%= 4

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2 years ago

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Margo freezes 8 cups of strawberries if this is 2/3 of the total strawberries that she picked how many cups of strawberries did

Goryan [66]

Answer:

12 cups.

Step-by-step explanation:

Let x be the total cups of strawberries picked by Margo.

We have been given that Margo freezes 8 cups of strawberries and this is 2/3 of the total strawberries that she picked.

We need to find x such that 2/3 of x equals 8. We can represent this information in an equation as:

$\frac{2}{3}x=8$

Let us multiply both sides of our equation by 3.

$3*\frac{2}{3}x=3*8$

$2x=24$

Let us divide both sides of our equation by 2.

$\frac{2x}{2}=\frac{24}{2}$

$x=12$

Therefore, Margo picked 12 cups of strawberries.

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3 years ago