The largest consecutive integers whose sum is less than 46 are x= 21 and x+1=22
Step-by-step explanation:
Let the integers be:
x and x+1
The sum of these integers is less than 46
Solving and finding value of x:
So, the integers will be less than 22.5
The largest numbers are: 21 and 22
So, the largest consecutive integers whose sum is less than 46 are x= 21 and x+1=22
Keywords: Finding integers
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Answer:5/12
Step-by-step explanation:
Answer:
coordinates of B is ( 4,5)
Step-by-step explanation:
If there two points (x1,y1) and (x2,y2) on a plane then coordinates of mid point is given by
m = (x1+x2)/2 , (y1+y2)/2
Given
m = (-1,1)
A= (-6, -3)
we have to point b
let point b be (x,y)
Then m (-1,1) is given by (-6+x)/2 , (-3+y)/2
(-6+x)/2 = -1
-6 + x = 2*-1 = -2
x = -2+6 = 4
also
(-3+y)/2 = 1
=> -3 + y = 2
=> y = 2 + 3 = 5
Thus , coordinates of B is ( 4,5) answer
Answer:
it is -12, -6, -4, -3, 1, 4
