Write a for loop to print all elements in courseGrades, following each element with a space (including the last). Print forwards
1 answer:
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Hi, you haven't provided the programing language in which you need the code, I'll explain how to do it using Python, and you can follow the same logic to make a program in the programing language that you need.
Answer:
import math
def rectangle(perimeter, area):
l1_1 = (perimeter+math.sqrt((perimeter**2)-(16*area)))/4
l1_2 = (perimeter-math.sqrt((perimeter**2)-(16*area)))/4
l2_1 = area/l1_1
l2_2 = area/l1_2
print(l1_1,l2_1)
print(l1_2,l2_2)
if l1_1.is_integer() and l2_1.is_integer() and l1_1>0 and l2_1>0:
return(int(max(l1_1,l2_1)))
elif l1_2.is_integer() and l2_2.is_integer() and l1_2>0 and l2_2>0:
return(int(max(l1_2,l2_2)))
else:
return(None)
Explanation:
- We import math to make basic operations
- We define the rectangle function that receives perimeter and area
- We calculate one of the sides (l1_1) of the rectangle using the quadratic equation to solve 2h^2 - ph + 2a = 0
- We calculate the second root of the quadratic equation for the same side (l1_2)
- We calculate the second side of the rectangle using the first root on w = a/h
- We calculate the second side of the rectangle using the second root on w= a/h
- We verify that each component of the first result (l1_1, l2_1) is an integer (using the build-in method .is_integer) and greater than 0, if True we return the maximum value between them (using the max function) as w
- If the first pair of sides evaluate to False we check the second root of the equation and if they meet the specification we return the max value
- if all the if statements evaluate to false we return None to indicate that not positive or integer sides were found
Answer:
Following are the code to this question:
import java.util.*;//import package for user input
public class Main//defining class main
{
public static boolean odd_number_digits(int n)//defining boolean method odd_number_digits
{
if(n>0 && n%2!=0)//defining if block that check value is positive and odd number
{
return true;//return value true
}
else//defining else block
{
return false;//return false value
}
}
public static void sum_odd_digits(int n)//defining a method sum_odd_digits
{
int sum=0,i;//defining integer variable
for(i=0;i<=n;i++)//defining for loop
{
if(i%2!=0)//defining if block for odd number
{
sum=sum+i;//add odd number
}
}
System.out.print(sum);//use print method to print sum value
}
public static void main(String[] args) //defining main method
{
Scanner ox=new Scanner(System.in);//creating Scanner object
int n= ox.nextInt();//defining integer variable for input value
System.out.print(odd_number_digits(n)+ "\n");//use print method to call method
System.out.println("Sum of odd numbers: ");//print message
sum_odd_digits(n);//calling method
}
}
Output:
please find the attachment.
Explanation:
In the above code, two methods "odd_number_digits and sum_odd_digits" are defined in which the first method return type is boolean because it will true or false value, and the second method returns the sum of odd numbers.
In the "odd_number_digits" method, an integer variable passes as an argument and inside the method, if block is used that check value is a positive and odd number then it will return a true value.
In the "sum_odd_digits" method, it accepts an integer parameter "n", and define integer variable "sum" inside the method, which uses the for loop, inside the loop if block is used that counts odd numbers and adds its in sum and print its value.
