Gold chest takes 8 hours to open or unlock.
<u>Explanation:</u>
Clash royale is a game which has been developed and published with the help of a super cell. It is a video game. Many players can play this game at the same time. In the sense, clash royale is a multi player game.
In this game, the players who are playing the game are awarded with the gold chest. They are also awarded with the gems. In order to unlock or open a gold chest eight hours are needed. Apart from this there is an other way also with which the gold chest can be unlocked. It can be unlocked with the help of forty eight gems.
Answer:
ssume that,
Maximum “students” count can be 10.
*Driver Class*
*Solution class*
import java.util.*;
class Student {
private String name;
private int rollNo;
public String getName() {}
public void setName(String name) {}
public int getRollNo() {}
public void setRollNo(int rollNo) {}
};
class ClassRoom {
private int i;
private Student[] students;
public void addStudent(String name, int rollNo) {}
public Student[] getAllStudents() {}
};
Note: The matrix referred to in the question is: ![M = \left[\begin{array}{ccc}1/2&1/3&0\\1/2&1/3&0\\0&1/3&1\end{array}\right]](https://tex.z-dn.net/?f=M%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%2F2%261%2F3%260%5C%5C1%2F2%261%2F3%260%5C%5C0%261%2F3%261%5Cend%7Barray%7D%5Cright%5D)
Answer:
a) [5/18, 5/18, 4/9]'
Explanation:
The adjacency matrix is
To start the power iteration, let us start with an initial non zero approximation,
![X_o = \left[\begin{array}{ccc}1\\1\\1\end{array}\right]](https://tex.z-dn.net/?f=X_o%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%5C%5C1%5C%5C1%5Cend%7Barray%7D%5Cright%5D)
To get the rank vector for the first Iteration:
![X_1 = \left[\begin{array}{ccc}1/2&1/3&0\\1/2&1/3&0\\0&1/3&1\end{array}\right]\left[\begin{array}{ccc}1\\1\\1\end{array}\right] \\\\X_1 = \left[\begin{array}{ccc}5/6\\5/6\\4/3\end{array}\right]\\](https://tex.z-dn.net/?f=X_1%20%3D%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%2F2%261%2F3%260%5C%5C1%2F2%261%2F3%260%5C%5C0%261%2F3%261%5Cend%7Barray%7D%5Cright%5D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%5C%5C1%5C%5C1%5Cend%7Barray%7D%5Cright%5D%20%5C%5C%5C%5CX_1%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D5%2F6%5C%5C5%2F6%5C%5C4%2F3%5Cend%7Barray%7D%5Cright%5D%5C%5C)
Multiplying the above matrix by 1/3
![X_1 = \left[\begin{array}{ccc}5/18\\5/18\\4/9\end{array}\right]](https://tex.z-dn.net/?f=X_1%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D5%2F18%5C%5C5%2F18%5C%5C4%2F9%5Cend%7Barray%7D%5Cright%5D)
The correct answer is letter B. Application Software. Word Processing software, spreadsheet software, database software, and presentation software are examples of Application software. These are applications that are mostly output based.
Answer:
The codes below implement the problem statements
Explanation:
public class Percentages {
public static void computePercent (int a,int b)
{
System.out.println(a+" is "+(a*100/b)+"% of "+b);
}
public static void main(String []args)
{
int a=2;
int b=5;
computePercent(a,b);
computePercent(b,a);
}
}
<u>
</u>
<u>Part(b)
</u>
import java.util.*;
public class Percentages {
public static void computePercent (int a,int b)
{
System.out.println(a+" is "+(a*100/b)+"% of "+b);
}
public static void main(String []args)
{
Scanner s= new Scanner(System.in);
int a=s.nextInt();
int b=s.nextInt();
computePercent(a,b);
computePercent(b,a);
}
}
