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2 years ago

A man that is 6 feet tall weighs 165 pounds. Use this information to predict the weight of a man that is 5

Mathematics

1 answer:

Zarrin [17]2 years ago

7 0

Answer:

151 pounds

Step-by-step explanation:

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Interval Notation <br> Inequality Notation <br> Pls help

Andrew [12]

Step-by-step explanation:

Interval notation

$[ 10, +\infty \rang$

Inequality Notation

$x \geq 10$

4 0

2 years ago

Describe the sample variance using words rather than a formula. do the same with the population variance

Korvikt [17]

The option D is the correct option.

According to the statement

we have to define the sample variance in the words.

So,

The sample variance is the sum of the squared deviations from the mean divided by the number of measurements minus one.

and in the case of the population variance it becomes

The population variance is the average of the squared distances of the measurements on all units in the population from the mean.

This is the method by which we define the sample variance and population variance.

So, The option D is the correct option.

Learn more about the VARIANCE here brainly.com/question/15858152

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1 year ago

What is the surface area of a cylinder with a diameter of 8 and a height of 18?Express the answer in terms of pi

viktelen [127]

Step-by-step explanation:

diameter: 8

radius: 4

height: 18

$A=2\pi rh+2\pi r^2\\A=2\pi(4)(18)+2\pi(4)^2\\A=2\pi(72)+2\pi(16)\\A=144\pi+32\pi\\A=176\pi$

4 0

3 years ago

The volume of a cube can be found using the equation V = s³, where V is the volume and s is the measure of one side of the cube.

Harrizon [31]

$V=s^3\\\\s^3=729\ in^3\\\\s=\sqrt[3]{729\ in^3}\\\\ s=\sqrt[3]{729} \ in$
Answer

$s=\sqrt[3]{9^3}\ in\\\\s=9\ in$

6 0

2 years ago

Read 2 more answers

What is the solution to sqrt 17-x=x+3? Show your work.

snow_lady [41]

Answer:

$x=1$

Step-by-step explanation:

Remember:

$(\sqrt[n]{a})^n=a\\\\(a+b)=a^2+2ab+b^2$

Given the equation $\sqrt{17-x}=x+3$ , you need to solve for the variable "x" to find its value.

You need to square both sides of the equation:

$(\sqrt{17-x})^2=(x+3)^2$

$17-x=(x+3)^2$

Simplifying, you get:

$17-x=x^2+2(x)(3)+3^2\\\\17-x=x^2+6x+9\\\\x^2+6x+9+x-17=0\\\\x^2+7x-8=0$

Factor the quadratic equation. Find two numbers whose sum be 7 and whose product be -8. These are: -1 and 8:

$(x-1)(x+8)=0$

Then:

$x_1=1\\x_2=-8$

Let's check if the first solution is correct:

$\sqrt{17-(1)}=(1)+3$

$4=4$ (It checks)

Let's check if the second solution is correct:

$\sqrt{17-(-8)}=(-8)+3$

$5\neq-5$ (It does not checks)

Therefore, the solution is:

$x=1$

3 0

2 years ago