I looked it up and it should be D. Nerve cells :)
Answer:
50%
Explanation:
Glucose is a simple sugar with a total of 6 carbon atoms in its structure. Pyruvate has a total of three carbon atoms. Two molecules of pyruvate are obtained per glucose by glycolysis. None of the carbon of glucose is released in the form of CO2 during glycolysis. Therefore, the radio-labeled C-1 of glucose will be the component of the carbon skeleton of one of the total of two pyruvate molecules produced during glycolysis. So, 50% of the pyruvate will exhibit radioactivity.
يعينك على خير ان شاءالله يارب وياك يارب وياك يارب وياك يارب وياك يارب وياك يارب وياك يارب وياك يارب وياك يارب وياك يارب وياك يارب وياك يارب وياك يارب وياك
Answer:Glycolysis: (p. 94; Fig. 6.7A-C)
Refers to:
Occurs:
Energy investment phase: Steps 1 – 4 C-C-C-C-C-C
2 ATP
How many ATP's required (used)?
Results in 2 molecules of 3 phosphoglyceraldehyde (G3P) C-C-C C-C-C
Note: Step 5 is an isomeration step between G3P & Dihydixyacetone phosphate
Energy yielding phase: Steps 6 – 10 (G3P) C-C-C C-C-C
Explanation:
The body has levels of organization that build on each other. Cells make up tissues, tissues make up organs, and organs make up organ systems. The function of an organ system depends on the integrated activity of its organs. For instance, digestive system organs cooperate to process food.
