Let EB and CF be two heights. Then quadrilateral EBCF is rectangle, so BC=EF=5 m. It is given that bases are BC=5 m and AD=11 m. Triangles ABE and DCF are congruent, thus,
Consider right triangle ABE, by the Pythagorean theorem
Answer: 
Answer:
Acute angle
Step-by-step explanation:
Since it's measure is less than 90 degrees
Answer:
a. x = 36
b. ∠(AN) = 144°
Step-by-step explanation:
All the angle in the circle should add up to 360°.
x + x + 4x + 4x = 360
2x + 8x = 360
10x = 360
x = 36
∠(AN) = 4x
∠(AN) = 4(36)
∠(AN) = 144°
Answer:
b= 322.8
Step-by-step explanation:
10.50a + 3.75b = 2071.50
10.50 (82) + 3.75b = 2071.50
861 + 3.75b = 2071.50
-861 -861
3.75b = 1210.5
/3.75 /3.75
b = 322.8
