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3 years ago

What is 18976 times by 34526????

Mathematics

2 answers:

dedylja [7]3 years ago

8 0

18976×34526=655,165,376

dolphi86 [110]3 years ago

6 0

Yur answer is <span>655165376 hope it helped</span>

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If sin=3 by 5 and cos =4 by 5 find tan

Afina-wow [57]

Answer:

Step-by-step explanation:

$tan = \frac{sin}{cos }$

=3/5 × 5/4

=15/20

7 0

3 years ago

The vertices of polygon ABCD are at A(1, 1), B(2, 3), C(3, 2), and D(2, 1). ABCD is reflected across the x-axis and translated 2

Lana71 [14]

-- Reflecting across the x-axis makes all the x-coordinates the negative of
what they were before the reflection. The y-coordinates don't change.

-- Translating 2 units up makes all the y-coordinates 2 greater than
they were before the translation. The x-coordinates don't change.

You didn't give us a list of new coordinates, so there's nothing
to match with.

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3 years ago

The graph of f(x)=x^2 is sketched in red and the graph of g(x) is sketched in blue. Use the translation rule and f(x)=x^2 to ide

Yuki888 [10]

We can use the vertex form of a quadratic, $y = a(x-h)^{2} + k$ , to find that $g(x) = a x^{2} - 7$ . Plugging $(x,y)$ ordered pairs into g(x), we see that a = 1. For example, for $(3, 2)$ , $2 = a * 3^{2} - 7$ . Solving for a gives 1.

3 0

2 years ago

Again ... Commute times in the U.S. are heavily skewed to the right. We select a random sample of 500 people from the 2000 U.S.

VladimirAG [237]

Answer:

We conclude that the mean commute time in the U.S. is less than half an hour.

Step-by-step explanation:

We are given that a random sample of 500 people from the 2000 U.S. Census is selected who reported a non-zero commute time.

In this sample the mean commute time is 27.6 minutes with a standard deviation of 19.6 minutes.

Let $\mu$ = <u><em>mean commute time in the U.S..</em></u>

So, Null Hypothesis, $H_0$ : $\mu \geq$ 30 minutes {means that the mean commute time in the U.S. is more than or equal to half an hour}

Alternate Hypothesis, $H_A$ : $\mu$ < 30 minutes {means that the mean commute time in the U.S. is less than half an hour}

The test statistics that would be used here <u>One-sample t-test statistics</u> as we don't know about population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean commute time = 27.6 minutes

s = sample standard deviation = 19.6 minutes

n = sample of people from the 2000 U.S. Census = 500

So, <u><em>the test statistics</em></u> = $\frac{27.6 -30}{\frac{19.6}{\sqrt{500} } }$ ~ $t_4_9_9$

= -2.738

The value of t test statistic is -2.738.

Since, in the question we are not given with the level of significance so we assume it to be 5%. <u>Now, at 5% significance level the t table gives critical values of -1.645 at 499 degree of freedom for left-tailed test.</u>

Since our test statistic is less than the critical value of t as -2.378 < -1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u>we reject our null hypothesis.</u>

Therefore, we conclude that the mean commute time in the U.S. is less than half an hour.

4 0

3 years ago

calculate the amount of money invested at 8.5% per annum when 2,488.80 simple interest was collected after three years. anyone

Mrac [35]

Answer:

2488.80 divided by 3=838.1

6 0

2 years ago