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Nataly_w [17]
3 years ago
7

342 employees prefer a bonus over extra vacation days from a survey of 450 employees what is the population proportion

Mathematics
1 answer:
salantis [7]3 years ago
8 0

Answer:

76

Step-by-step explanation:

450/100 = 4.5

342/4.5 = 76

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The linear equation has 5(x + 2) = 5x + 2 A) no solution. B) one solution. C) two solutions. D) infinitely many solutions.
erik [133]
I would say C!!!!!!!!!
4 0
3 years ago
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How do you solve (Arc)QPT if <QZT = 120
yuradex [85]
By definition, the arc length is given by:
 arc = R * theta * ((2 * pi) / 360)
 Where,
 theta: angle in degrees
 R: radio
 We have then:
 (Arc) QPT if <QZT = 120:
 theta = 360-120 = 240 degrees
 R = 13.5 units
 Substituting values we have:
 (Arc) QPT = R * theta * ((2 * pi) / 360)
 (Arc) QPT = (13.5) * (240) * ((2 * pi) / 360)
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 Answer:
 
(Arc) QPT = 56.55 units
7 0
3 years ago
I’ve been stuck on this for a min now
dedylja [7]

Answer:

3/14

Step-by-step explanation:

1st subtract the y's

the subtract the x's in the same order

-9 - 5 = -14

put the first result over the second

-3/-14 = 3/14

4 0
2 years ago
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Sati [7]

Answer:

The Indus River Valley Civiization.

Step-by-step explanation:

https://www.history.com/topics/ancient-middle-east/persian-empire#section_1

7 0
3 years ago
Arrange the geometric series from least to greatest based on the value of their sums.
son4ous [18]

Answer:

80 < 93 < 121 < 127

Step-by-step explanation:

For a geometric series,

\sum_{t=1}^{n}a(r)^{t-1}

Formula to be used,

Sum of t terms of a geometric series = \frac{a(r^t-1)}{r-1}

Here t = number of terms

a = first term

r = common ratio

1). \sum_{t=1}^{5}3(2)^{t-1}

   First term of this series 'a' = 3

   Common ratio 'r' = 2

   Number of terms 't' = 5

   Therefore, sum of 5 terms of the series = \frac{3(2^5-1)}{(2-1)}

                                                                      = 93

2). \sum_{t=1}^{7}(2)^{t-1}

   First term 'a' = 1

   Common ratio 'r' = 2

   Number of terms 't' = 7

   Sum of 7 terms of this series = \frac{1(2^7-1)}{(2-1)}

                                                    = 127

3). \sum_{t=1}^{5}(3)^{t-1}

    First term 'a' = 1

    Common ratio 'r' = 3

    Number of terms 't' = 5

   Therefore, sum of 5 terms = \frac{1(3^5-1)}{3-1}

                                                 = 121

4). \sum_{t=1}^{4}2(3)^{t-1}

    First term 'a' = 2

    Common ratio 'r' = 3

    Number of terms 't' = 4

    Therefore, sum of 4 terms of the series = \frac{2(3^4-1)}{3-1}

                                                                       = 80

    80 < 93 < 121 < 127 will be the answer.

4 0
3 years ago
Read 2 more answers
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