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3 years ago

Please help with this! What equations are equivalent to 1/3^8

1 answer:

4 0

I don’t know how to sorry

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ANTONII [103]

first and second part put 0.75, then multiply 0.75 by 2 to get 1.50, then write in the third part 1 and 1/2

hope this helps

6 0

3 years ago

8090 [49]

Answer:yes

Step-by-step explanation:

7 0

3 years ago

kondaur [170]

Ok, if you decrease <span>£2500 by 1% you get 99% remaining
</span>So
99% of £2500 = 0.99 x £2500 = <span>£2475</span>

6 0

3 years ago

Akimi4 [234]

Answer:

Step-by-step explanation:

The double negatives turn into a positive which makes the problem 3+2 which equals 5.

3 0

4 years ago

Mademuasel [1]

Answer:- a.The given expression is equivalent to $\frac{x^{10}y^{14}}{729}$

Given expression:- $[\frac{(3xy^{-5})^3}{(x^{-2}y^2)^{-4}}]^{-2}$

$=[\frac{(3)^3x^3y^{-5\times3}}{x^{-2\times-4}y^{2\times-4}}]^{-2}.........(a^m)^n=a^{mn}$

$=[\frac{27x^3y^{-15}}{x^8y^{-8}}]^{-2}$

$=[27x^{3-8}y^{-15-(-8)}]^{-2}............\frac{a^m}{a^n}=a^{m-n}$

$=[27x^{-5}y^{-7}]^{-2}=(27)^{-2}(x^{-5})^{-2}(y^{-7})^{-2}.........(a^m)^n=a^{mn}$

$=\frac{1}{(27)^2}(x^{10}y^{14})=\frac{x^{10}y^{14}}{729}$

Thus a. is the right answer.

6 0

3 years ago