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zheka24 [161]
3 years ago
10

Write this polynomial in standard form :8x^2 - 4x^3 + 12 - 5x

Mathematics
1 answer:
rodikova [14]3 years ago
3 0

Hello from MrBillDoesMath

Answer:  -4x^3 + 8x^2 -5x + 12

Discussion:

Standard for for a polynomial meas tne power of x descend so standard fro of

8x^2 - 4x^3 +12 -5x  is

-4x^3 + 8x^2 -5x + 12

Note: the problem statements shows this ":8x^2". I didn't know how to deal with the ":" character so simply ignored it.

Thank you,

Mr. B

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The table displays data for Nutrition Guides of a single serving of particular foods. Assuming there exists a correlation betwee
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Step-by-step explanation:

Step 1: Find X⋅Y and  as it was done in the table below.

Step 2: Find the sum of every column:

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Step 3: Use the following equations to find a and b:

a  =  = -2.105

b = \frac{n.\sum{XY}  -   \sum{X}.\sum{Y}}{n.\sum{(X^{2})}- (\sum{X})^{2} } = 0.054

Step 4: Substitute a and b in regression equation formula

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Answer:

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Step-by-step explanation:

A set of normally distributed data has a mean of 3.2 and a standard deviation of 0.7. Find the probability of randomly selecting 30 values and obtaining an average greater than 3.6.

We can denote the population mean with the symbol \mu

According to the information given, the data have a population mean:

\mu = 3.2.

The standard deviation of the data is:

\sigma = 0.7.

Then, from the data, a sample of size n = 30 is taken.

We want to obtain the probability that the sample mean is greater than 3.6

If we call

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P(\mu_m> 3.6)

To find this probability we find the Z statistic.

Z = \frac{\mu_m-\mu}{\sigma_{\mu_m}}

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Where \sigma_{\mu_m} is the standard deviation of the sample

\sigma_{\mu_m} = \frac{\sigma}{\sqrt{n}}

\sigma_{\mu_m} =\frac{0.7}{\sqrt{30}}\\\\\sigma_{\mu_m} = 0.1278

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