I drew the segment and used Pythagorean theorem to solve for its measure. The line formed is the hypotenuse of the imaginary right triangle.
Among the choices only -1.33 and -1.25 is a feasible choice. But I am leaning towards -1.25 as the y-value of point F based on my diagram. Please see attachment.
Let
A(4,5) B(8,7) C(12,9) D(16,11)
1) Find the slope AB
m=(y2-y1)/(x2-x1)
m=(7-5)/(8-4)=0.5
2) Find the slope BC
m=(9-7)/(12-8)=0.5
3) Find the slope CD
m=(11-9)/(16-12)=0.5
The points represent a linear function
so
<u>Find the equation of the line with m=0.5 and the point A(4,5)</u>
we know that
y-y1=m*(x-x1)
y-5=0.5*(x-4)
y=0.5*x-2+5
y=0.5*x+3
therefore
<u>the answer is</u>
The equation is equal to y=0.5*x+3
Answer:
So we have an original figure with a value of 50 and then a scaled version or dilation
Hence we have a scale factor of
We know that
[perimeter of rectangle]=2*(<span>length+width)
</span>
Let
x-----------> length
y-----------> width
so
P=2*(x+y)-----------> 244=2*(x+y)-----> x+y=122-------> y=122-x
Area=x*y-------> x*(122-x)----> 122x-x²
find the derivative function and equals to zero
122-2x=0-----> 122=2x----------> x=61 m
y=122-x------> y=122-61---------> y=61 m
<span>the maximum area is given by a square
</span>
the answer is
is a square of side 61 m
