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Inga [223]
3 years ago
6

Please help will mark brainliest

Mathematics
2 answers:
Advocard [28]3 years ago
7 0

Answer:

y=-1/2x+8

Step-by-step explanation:

expeople1 [14]3 years ago
7 0
Y =-1/2x+8 1+2=3 3+8=9
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When x = 3 and y = 5, by how much does the value of 3x^2 – 2y exceed the value of 2x^2 – 3y ?
JulsSmile [24]
3\cdot3^2-2\cdot5-(2\cdot3^2-3\cdot5)=27-10-(18-15)=17-3=14
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3 years ago
What is 125 centimeters to 87.5 centimeters
bagirrra123 [75]
If you are asking how to subtract 125 centimeters and make it 87.5, you have to subtract from 125. The easiest way to do this is to subtract 87.5 from 125, getting 37.5. So, if you add 37.5 to 87.5, you will have 125. So, the correct answer is to subtract 37.5 to get 87.5.
3 0
3 years ago
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Which of the following congruency statements is correct? Yzx = bcd, yzx = dcb, zxy =dcb, yxz = cdb
goldenfox [79]

Answer:c

Step-by-step explanation:

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2 years ago
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Complete the table... plz help ​
ICE Princess25 [194]

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Step-by-step explanation:

4 0
3 years ago
XY is a diameter of a circle and Z is a point on the circle such that ZY=6. If the area of the triangle XYZ is 18 square root 3
nataly862011 [7]
<h2>Answer:</h2>

4π

<h2>Step-by-step explanation:</h2>

As shown in the diagram, triangle XYZ is a right triangle. Therefore, its area (A) is given by:

A = \frac{1}{2} x b x h      -------------(i)

Where;

A = 18\sqrt{3}

b = XZ = base of the triangle

h = YZ = height of the triangle = 6

<em>Substitute these values into equation(i) and solve as follows:</em>

18\sqrt{3} =  \frac{1}{2} x b x 6

18\sqrt{3} =  3b

<em>Divide through by 3</em>

6\sqrt{3} =  b

Therefore, b = XZ = 6\sqrt{3}

<em>Now, assume that the circle is centered at O;</em>

Triangle XOZ is isosceles, therefore the following are true;

(i) |OZ| = |OX|

(ii) XZO = ZXO = 30°

(iii) XOZ + XZO + ZXO = 180°   [sum of angles in a triangle]

=>  XOZ + 30° + 30° = 180°

=>  XOZ + 60° = 180°

=>  XOZ = 180° - 60°

=>  XOZ = 120°

Therefore we can calculate the radius |OZ| of the circle using sine rule as follows;

\frac{sin|XOZ|}{XZ} = \frac{sin|ZXO|}{OZ}

\frac{sin120}{6\sqrt{3} } = \frac{sin 30}{OZ}

\frac{\sqrt{3} /2}{6\sqrt{3} } = \frac{1/2}{|OZ|}

\frac{1}{12}  = \frac{1}{2|OZ|}

\frac{1}{6} = \frac{1}{|OZ|}

|OZ| = 6

The radius of the circle is therefore 6.

<em>Now, let's calculate the length of the arc XZ</em>

The length(L) of an arc is given by;

L = θ / 360 x 2 π r          ------------------(ii)

Where;

θ = angle subtended by the arc at the center.

r = radius of the circle.

In our case,

θ = ZOX = 120°

r = |OZ| = 6

Substitute these values into equation (ii) as follows;

L = 120/360 x 2π x 6

L = 4π

Therefore the length of the arc XZ is 4π

5 0
2 years ago
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