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3 years ago

F(1) = 55, f(n)=f(n - 1) +8; 95 The term 95 is the _th term Need help quickly

Mathematics

1 answer:

Viefleur [7K]3 years ago

5 0

Answer:

6th term

Step-by-step explanation:

95=55+8n-8

95-55=8n-8

40+8=8n

48/8=8n/8

6=n

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2. The number of nickels that Christine has is

aev [14]

Answer:

The number of nickels is 15

The number of Dimes is 3

Step-by-step explanation:

Let the number of dimes Christine has be d

The number of nickels with christine be n

Then the number of Nickels Christine has will be

n = 5d ----------------------------------(1)

Now The total value of both dimes and nickels is = $1.05

This can be represented as

5n +10d = 105 (in cents)

From eq(1)

5(5d) + 10d = 105

25d+10d = 105

35d = 105

$d = \frac{105}{35}$

d = 3----------------------------------(2)

Substituting (2) in (1), we get

n = 5(3)

n = 15

7 0

3 years ago

sandra used 2 jars of beads to make 16 necklaces how many jars of beads would she need to make 192 neclaces

garik1379 [7]

Answer:

24 Jars

Step-by-step explanation:

Do 16/2, which gives you eight for every necklace. Then do 192/8 which would give you 24. So, she would need 24 jars for 192 necklaces.

4 0

3 years ago

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How many place values follow the decimal point in the problem below?<br> 2.01 x 4.1

MakcuM [25]

Answer:

Step-by-step explanation:

There are 3 digits behind the decimal all together

8 0

3 years ago

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A business man has 200 bags of maize flour each weighing 50000 grammes. Find the total weight of the bags in kilograms

____ [38]

Answer:

10,000 ★ soz if im wrong

Step-by-step explanation:

I hope the best

6 0

2 years ago

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For each initial value problem, determine whether Picard's Theorem can be used to show the existence of a unique solution in an

Alinara [238K]

Answer:

Part a: $f , \, f_y$ is continuous at the initial value (0,0) so due to Picardi theorem there exists an interval such that the IVP has a unique solution.

Part b: $f_y$ is not continuous at the initial value (0,0) so due to Picardi theorem there does not exist an interval such that the IVP has a unique solution.

part c: $f , \, f_y$ is continuous at the initial value (0,1) so due to Picardi theorem there exists an interval such that the IVP has a unique solution.

Step-by-step explanation:

Part a

as $y^{' }=ty^{4/3}$

Let

$f(t,y)=ty^{4/3}$

Now derivative wrt y is given as

$f_y=\frac{4}{3}ty^{1/3}$

Finding continuity via the initial value

$f$ is continuous on $R^2$ also $f_y$ is also continuous on $R^2$

Also

$f , \, f_y$ is continuous at the initial value (0,0) so due to Picardi theorem there exists an interval such that the IVP has a unique solution.

Part b

as $y^{' }=ty^{1/3}$

Let

$f(t,y)=ty^{1/3}$

Now derivative wrt y is given as

$f_y=\frac{1}{3}ty^{-2/3}$

Finding continuity via the initial value

$f$ is continuous on $R^2$ also $f_y$ is also continuous on $R^2$

Also

$f_y$ is not continuous at the initial value (0,0) so due to Picardi theorem there does not exist an interval such that the IVP has a unique solution.

Part c

as $y^{' }=ty^{1/3}$

Let

$f(t,y)=ty^{1/3}$

Now derivative wrt y is given as

$f_y=\frac{1}{3}ty^{-2/3}$

Finding continuity via the initial value

$f$ is continuous on $R^2$ also $f_y$ is also continuous on $R^2$ when $y\neq 0$

Also

$f , \, f_y$ is continuous at the initial value (0,1) so due to Picardi theorem there exists an interval such that the IVP has a unique solution.

6 0

3 years ago