Please helpp meeee!!!

Mathematics

1 answer:

Law Incorporation [45]3 years ago

5 0

Answer:

im pretty sure the answer would be,

$2 \frac{1}{2}$

Step-by-step explanation:

the median is the middle number of the data, and since there are two medians, you find the mean of the two numbers by adding them together, and then you divide it by 2.

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Find the perimeter of a field that has length 2/x + 1 and width 5/x^2 -1.

Semmy [17]

Answer:

D)4x + 6/(x + 1)(x - 1)

Step-by-step explanation:

A field is basically a rectangle, so to find the perimeter of our field we are using the formula for the perimeter of a rectangle

$p=2(l+w)$

where

$p$ is the perimeter

$l$ is the length

$w$ is the width

We know from our problem that the field has length 2/x + 1 and width 5/x^2 -1, so $l=\frac{2}{x+1}$ and $w=\frac{5}{x^2-1}$ .

Replacing values:

$p=2(l+w)$

$p=2(\frac{2}{x+1} +\frac{5}{x^2-1})$

Notice that the denominator of the second fraction is a difference of squares, so we can factor it using the formula $a^2-b^2=(a+b)(a-b)$ where $a$ is the first term and $b$ is the second term. We can infer that $a=x^2$ and $b=1^2$ . So, $x^2-1=(x+1)(x-1)$ . Replacing that: