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Reptile [31]
3 years ago
15

If John's home is worth $145,300, how much is his coverage for living expenses if insurance covers 20 percent?

Mathematics
2 answers:
suter [353]3 years ago
8 0
145,300 X .2 = 29,060

you multiply .2 because that is equal to 20% in decimal form, and you are finding out how much the insurance covers

therefore your answer would be 29,060 dollars
Dahasolnce [82]3 years ago
7 0

Answer:

Step-by-step explanation:

Alright, lets get started.

The worth is John's home is : 145300

The insurance covers 20 % of it, so

coverage will be = 145300*20%

coverage will be = 145300*\frac{20}{100}

Coverage will be = 145300*.2 = 29060

So the answer is $ 29060    :    Answer

Hope it will help :)

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plz help ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
katen-ka-za [31]

Answer:

B. $5039.58

Step-by-step explanation:

compound interest formula: amount = p(1 + \frac{r}{n})^{nt}

p= principal ($2,300)

r= interest rate as a decimal (4% = 0.04)

n= number of times the principal is compounded per year (annually = onceper year so 1 time per year)

t= time in years (20 years)

new equation: amount = 2300(1+\frac{0.04}{1} )^{1*20}

That equation equals $2,739.58 which you add to the principal.

$2,739.58 + $2,300 = $5039.58

hope this helps :)

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