Hey ! there
Answer:
- Value of missing side i.e. TE is <u>1</u><u>2</u><u> </u><u>feet</u>
Step-by-step explanation:
In this question we are provided with a <u>right</u><u> </u><u>angle </u><u>triangle</u> having <u>TS </u><u>-</u><u> </u><u>35</u><u> </u><u>ft </u><u>and</u><u> </u><u>SE </u><u>-</u><u> </u><u>37</u><u> </u><u>ft </u>. And we are asked to find the missing side that is <u>TE </u>using Pythagorean Theorem .
<u>Pythagorean Theorem :</u> -
According to Pythagorean Theorem sum of squares of perpendicular and base is equal to square of hypotenuse in a right angle triangle i.e.
<u>Where </u><u>,</u>
- H refers to <u>Hypotenuse</u>
- P refers to <u>Perpendicular</u>
<u>Solution</u><u> </u><u>:</u><u> </u><u>-</u>
In the given triangle ,
- Perpendicular = <u>TS </u><u>(</u><u> </u><u>35</u><u> </u><u>feet </u><u>)</u>
- Hypotenuse = <u>SE </u><u>(</u><u> </u><u>37</u><u> </u><u>feet </u><u>)</u>
Now applying Pythagorean Theorem :

Substituting values :

Simplifying it ,

Subtracting 1225 on both sides :

We get ,

Applying square root to both sides :

We get ,

- <u>Henceforth</u><u> </u><u>,</u><u> </u><u>value </u><u>of </u><u>missing </u><u>side </u><u>is </u><em><u>1</u></em><em><u>2</u></em><em><u> </u></em><em><u>feet </u></em><em><u>.</u></em>
<u>Verifying</u><u> </u><u>:</u><u> </u><u>-</u>
Now we are verifying our answer using Pythagorean Theorem . We know that according to Pythagorean Theorem ,
Substituting value of SE , TS and TE :
- 37² = 35² + <u>1</u><u>2</u><u>²</u>
<u>Therefore</u><u> </u><u>,</u><u> </u><u>our</u><u> answer</u><u> is</u><u> correct</u><u> </u><u>.</u>
<h2>
<u>#</u><u>K</u><u>e</u><u>e</u><u>p</u><u> </u><u>Learning</u></h2>
1. We know that 30% expressed as a decimal is 0.30
Since 30% of people were using the internet, 0.30*3200 is our answer.
3200*0.30= 960.
Therefore 960 people were using the internet out of the 3200 surveyed.
5x - 3y = 11 ⇒ 5x - 3y = 11 ⇒ 5x - 3y = 11
x - 2y = 2 ⇒ -5(x - 3y) = 2 ⇒ <u>-5x + 15y = 2</u>
<u>12y</u> = <u>13</u>
12 12
y = 1 1/12
5x - 3(1 1/12) = 11
5x - 3 1/4 = 11
<u> +3 1/4 +3 1/4</u>
<u> 5x</u> = <u>14 1/4</u>
5 5
x = 2 17/20
(x, y) = (2 17/20, 1 1/12)
4 * 2 = 8
8 + 5 = 13
B, is the correct answer