Question

Here is a circle, centre 0, and the tangent to the circle at the

Answer 1

Answer:

$y = \dfrac{7}{24}x + \dfrac{625}{24}$

Step-by-step explanation:

The radius drawn to the tangent at the point of tangency is perpendicular to the tangent.

The radius has endpoints (0, 0) and (-7, 24). The slope of the line containing the radius is

$m_r = \dfrac{24 - 0}{-7 - 0}$

$m_r = -\dfrac{24}{7}$

The slope of the tangent is the negative reciprocal of the slope of the radius.

$m_t = \dfrac{7}{24}$

The tangent contains point (-7, 24).

y = mx + b

$24 = \dfrac{7}{24}(-7) + b$

$24 = -\dfrac{49}{24} + b$

$\dfrac{576}{24} + \dfrac{49}{24} = b$

$b = \dfrac{625}{24}$

The equation of the tangent is

$y = \dfrac{7}{24}x + \dfrac{625}{24}$