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finlep [7]
3 years ago
5

Isoceles and Equalateral Triangles. Need help fast​

Mathematics
2 answers:
romanna [79]3 years ago
6 0

Answer: 60

Step-by-step explanation:  An acute triangle must have angles that added up equal 180 degrees. The angles are the same value, and 60 times the three angles gives us 180.

Iteru [2.4K]3 years ago
4 0

Answer:

d

Step-by-step explanation:

the angle measures in all equilateral triangles are the same

so divide 180 by 3 and you get 60

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PLEASE HELP!!! i’ll give brainliest
tekilochka [14]

Answer:

x = \sqrt{164

Step-by-step explanation:

In order to find the hypothenuse, you need to do 8^{2}  + 10^{2}. Which equals 164. Therefore, since a^{2} +b^{2} =c^{2}, a=8, b=10, and c=\sqrt{164.

8 0
3 years ago
Which of the following statements is true? Will mark BRAINLIEST if the answer is right. 20 points!
frutty [35]

Answer:

this (。ŏ_ŏ) statement is correct.

J) 180° - m<7 = m<1

4 0
3 years ago
If f (x) = x and g(x) = 3x + 1 are two real functions. Find (f + g) (x)
romanna [79]

Answer:

4x + 1

Step-by-step explanation:

note that (f + g)(x) = f(x) + g(x) , thus

f(x) + g(x)

= x + 3x + 1 ← collect like terms

= 4x + 1

4 0
4 years ago
Write each expression in terms of sines and/or cosines and then simplify.
Sedaia [141]
Tan(x)= sin(x)/cos(x), therefore, substitute sin(x)/cos(x) in the expression:
=(cos(x)(sin(x)/cos(x))-1)/cos^2(x)
simplify the 2 cos(x):
=(sin(x)-1)/cos^2(x)
Sin^2(x)+ cos^2(x)=1, sin^2(x)-1=- cos^2(x), substitute in the expression:
= -cos^2(x)/cos^2(x)= -1
8 0
3 years ago
Answer the problem :)
Tomtit [17]
The domain is the value of x. In this case, -3≤x≤7
the range is the value of y. in this case, -1≤y≤9

this is not a function, because the same x value has two corresponding y values. For example, when x=5, y=0 or y=8

It IS a function if every x value has only one corresponding y value. 
5 0
3 years ago
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