Answer:
Answer below!
Explanation: Mean -- add all of the values and divide by the total number of data points.
Error -- subtract the theoretical value (usually the number the professor has as the target value) from your experimental data point.
Percent error -- take the absolute value of the error divided by the theoretical value, then multiply by 100
Answer:
a) 
b) 
c) 
Explanation:
Hola.
Para resolver los numerales a), b) y c), debemos seguir los siguientes procedimientos:
a) En este caso, primeo calculamos la masa que 45.9 cm³ ocupan con una densidad 0.924 g/cm³ como se muestra a continuación:

Seguidamente, sabiendo que estos gramos ocupan 0.275 moles, podemos facilmente calcular la masa molar como la relación entre ellas:

b) En este caso, como se tienen 120 cm³ calculamos la nueva masa:

Luego, con la masa molar, las moles:

Finalmente, con el número de Avogadro, las moléculas presentes:

c) Aquí, consideramos que hay una molécula de la sustancia, por lo que usando el número de Avogadro, podemos calcular las moles que una molécula tiene:

Luego, usando la masa molar, calculamos la masa de una molécula:

¡Saludos!
A nuclear reaction involves the reaction of nuclei of atoms. This can be expressed in the form of nuclear equation in which the reactant nuclei are represented by their respective symbols carrying two numbers, the mass number denoted by A present at the top left and the atomic number (Z) written at the bottom left of the symbol of the element's nucleus.
The given nuclear reaction is the fusion of two isotopes of hydrogen, H-2 to form Helium-3 nucleus:

This reaction produces a single neutron.
Answer:
N-1
Explanation:
All nitrogen positions in purine rings (N-1, N-3, N-7 and N-9) have the potential to form hydrogen bonds. Among them, only N-1 is involved in Watson-Crick base pairing hydrogen bond with a pyridimine. N-3 and N-7 are available to form further hydrogen bonds and N-9 is involved in a N-glycosyl linkage with a desoxyribose.