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Tatiana [17]
3 years ago
14

Write balanced equations for each of the processes described below. (Use the lowest possible coefficients. Omit states-of-matter

.)
a. Chromium-51, which targets the spleen and is used as a tracer in studies of red blood cells, decays by electron capture.
b. Iodine-131, used to treat hyperactive thyroid glands, decays by producing a β particle.
c. Phosphorus-32, which accumulates in the liver, decays by β-particle production.
Chemistry
1 answer:
Aleks [24]3 years ago
7 0

Answer:

d

Explanation:

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Photochemical smog results from the interaction of pollutants in the presence of
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The water in a pressure cooker boils at a temperature greater than 100°C because it is under pressure. At this higher temperatur
vazorg [7]

Answer:

the activation energy Ea = 179.176 kJ/mol

it will take  7.0245 mins for the same food to cook in an open pot of boiling water at an altitude of 10000 feet.

Explanation:

From the given information

T_1 = 100^0 C = 100+273 = 373 \ K \\ \\  T_2 = 113^0 C = 113 + 273 = 386 \ K

R_1 = \dfrac{1}{7}

R_2 = \dfrac{1}{49}

Thus; \dfrac{R_2}{R_1} = 7

Because at 113.0°C; the rate is 7 time higher than at 100°C

Hence:

In (7) = \dfrac{Ea}{8.314}( \dfrac{1}{373}- \dfrac{1}{386})

1.9459 = \dfrac{Ea}{8.314}* 9.0292  *10^{-5}

1.9459*8.314 = Ea * 9.0292*10^{-5}

16.1782126= Ea * 9.0292*10^{-5}

Ea = \dfrac{16.1782126}{ 9.0292*10^{-5}}

Ea = 179.176 kJ/mol

Thus; the activation energy Ea = 179.176 kJ/mol

b)

here;

T_2 = 386 \  K  \\ \\T_1 = (89.8 + 273)K = 362.8 \ K

In(\dfrac{R_2}{R_1})= \dfrac{Ea}{R}(\dfrac{1}{T_1}- \dfrac{1}{T_2})

In(\dfrac{R_2}{R_1})= \dfrac{179.176}{8.314}(\dfrac{1}{362.8}- \dfrac{1}{386})

In (\dfrac{R_2}{R_1}) = 0.00357

\dfrac{R_2}{R_1}= e^{0.00357}

\dfrac{R_2}{R_1}= 1.0035

where ;

R_2 = \dfrac{1}7{}

R_1 = \dfrac{1}{t}

Now;

\dfrac{t}{7}= 1.0035

t = 7.0245 mins

Therefore; it will take  7.0245 mins for the same food to cook in an open pot of boiling water at an altitude of 10000 feet.

4 0
3 years ago
Which statement about the greenhouse effect is NOT true?
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<span> Greenhouse gases were not historically present in the atmosphere.</span>
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Calculate the atomic mass of nitrogen if the two common isotopes of
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Answer:

Atomic mass of nitrogen = 14.0067 amu.

Explanation:

Isotopes can be defined as two or more forms of a chemical element that are made up of equal numbers of protons and electrons but different numbers of neutrons.

Generally, the isotopes of a chemical element have the same chemical properties because of their atomic number but different physical properties due to their atomic weight (mass number).

The two isotopes of nitrogen are nitrogen-14 and nitrogen-15.

Given the following data;

Relative abundance of N-14 = 99.63%

Atomic mass of N-14 = 14.003

Relative abundance of N-15 = 0.37%

Atomic mass of N-15 = 15.000

The atomic mass is;

14.003 × (99.63/100) + 15.000 × (0.37/100)

Atomic mass = 14.003 × (0.9963) + 15.000 × (0.0037)

Atomic mass = 13.9512 + 0.0555

Atomic mass = 14.0067 amu.

<em>Therefore, the atomic mass of nitrogen is 14.0067 amu. </em>

3 0
3 years ago
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