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3 years ago

14

What's 21/50 in simplest form

2 answers:

lesya [120]3 years ago

7 0

21／50 already in simplest form

andreev551 [17]3 years ago

5 0

21/50

21/50 is in its most simple form because it cannot be broken down any further.

Answer: 21/50

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Rewrite the expression as a single exponent

kifflom [539]

Answer:

9^7

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

16. Solve for the angle x.<br> cos(¹/2x) = ¹/2

Basile [38]

Answer:

We know that ,

$\rightarrow \tt \cos( \frac{\pi}{3} ) = \frac{1}{2}$

So ,

$\: \rightarrow \tt \cos( \frac{1}{2}x ) = \cos( \frac{\pi}{3} ) \\ \\ \rightarrow \tt \frac{1}{2}.x = \frac{\pi}{3} \\ \\ \rightarrow \tt x = \frac{2\pi}{3}$

we can add 2 pi to it since there will be no change in the value

Also,

$\: \rightarrow \tt \cos( \frac{14\pi}{6} ) = \frac{1}{2} \\ \\ \\ \rightarrow \tt \frac{1}{2} x = \frac{14\pi}{6} \\ \\ \rightarrow \tt x = \frac{7\pi}{3}$

Answer : Option B

6 0

2 years ago

At time t ≥ 0, the velocity of a body moving along the s-axis is v = t² -5t +4. When is the body moving backwards

katovenus [111]

Answer:

A

Step-by-step explanation:

The velocity of a moving body is given by the equation:

$v=t^2-5t+4 ,\, t\geq0$

Is the velocity is <em>positive </em>(v>0), then our object will be moving <em>forwards</em>.

And if the velocity is negative (v<0), then our object will be moving <em>backwards</em>.

We want to find between which interval(s) is the object moving backwards. Hence, the second condition. Therefore:

$v$

By substitution:

$t^2-5t+4$

Solve. To do so, we can first solve for <em>t</em> and then test values. By factoring:

$(t-4)(t-1)=0$

Zero Product Property:

$t=1, \text{ and } t=4$

Now, by testing values for t<1, 1<t<4, and t>4, we see that:

$v(0)=4>0,\, v(2)=-20$

So, the (only) interval for which <em>v</em> is <0 is the second interval: 1<t<4.

Hence, our answer is A.

7 0

3 years ago

If u(x) = x^5 – x^4 + x^2 and v(x) = –x^2, which expression is equivalent to (u/v)(x)?

Effectus [21]

Hello:
x^5 – x^4 + x^2 =x^2(x^3 - x^2 +1)
(u/v)(x)= x^2(x^3 - x^2 +1)/(-x^2)
(u/v)(x)= - (x^3 - x^2 +1) = -x^3+x^2-1 ( x : no zero)

7 0

3 years ago

Solve: 2 + = 2. Give solutions in interval [0, 2)

Dovator [93]

$\because\cos 2x+\sin x=\sin 2x$ $\because\sin 2x=2\sin xcosx$ $\because\cos 2x=\cos ^2x-\sin ^2x$

→ Substitute cos 2x and sin 2x by their expressions

$\therefore\cos ^2x-\sin ^2+\sin x=2\sin x\cos x$

→ Subtract both sides by sin x

$\cos ^2x-\sin ^2x=2\sin xcosx-\sin x$

→ Take sin x as a common factor in the right side

$\therefore\cos ^2x-\sin ^2x=\sin x(2\cos x-1)$

From the graph, the equation has 4 solutions, the intersection points between the 2 graphs

7 0

1 year ago