Answer:
Step-by-step explanation:
<u>Volume And Function
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Geometry can usually be joined with algebra to express volumes as a function of some variable. The volume of a parallelepiped of dimensions a,b,c is
Our problem consists in computing the volume of a box made with some sheet of metal 12 ft by 18 ft. The four corners are cut by a square distance x as shown in the image below
.
If the four corners are to be lifted and a box formed, the base of the box will have dimensions (12-2x)(18-2x) and the height will be x. The volume of the box is
Operating and simplifying
I think the answer is b -3.
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Answers:
What is the ratio? 120:2
What is the unit rate? 60:1
What is the rate? 60 jumping jacks per minute
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Further Explanation:
To find the ratio of jumping jacks to minutes, you just write the two values 120 and 2 separated by a colon. That's how we get 120:2 as our first answer.
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Once we have 120:2, we divide both parts by 2 to get 60:1
120/2 = 60
2/2 = 1
The reason why we do this is so that the "2 minutes" turns into "1 minute". A unit ratio has the time value in unit increments so we can see how many jumping jacks Samuel can do. Writing "60:1" means "60 jumping jacks in 1 minute"
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Saying "60 jumping jacks in 1 minute" is the same as saying "60 jumping jacks per minute", which is similar to a car's speed of something like 60 miles per hour. The unit "X per Y" is the template for speed, where X is the number of items you get done and Y is the unit of time. In this case, X = 60 jumping jacks and Y = 1 minute.
Answer:
C. Over the interval [–1, 0.5], the local minimum is 1.
Step-by-step explanation:
From the graph we observe the following:
1) x intercepts are two points.
ii) y intercept = 1
f(x) = y increases from x=-infinity to -1.3
y decreases from x=-1.3 to 0
Again y increases from x=0 to end of graph.
Hence in the interval for x as (-1.3, 1) f(x) has a minimum value of (0,1)
i.e. there is a minimum value of 1 when x =0
Since [-1,0.5] interval contains the minimum value 1 we find that
Option C is right answer.
There is a local minimum of 1 in the interval [-1,0.5]