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Alona [7]
2 years ago
9

Please help me with this question I took a picture of it

Mathematics
1 answer:
Juli2301 [7.4K]2 years ago
8 0

Answer:

40

Step-by-step explanation:

36 = 90% × (number of questions)

36/0.90 = (number of questions) = 40 . . . . . divide by the coefficient of the variable

There were 40 questions on the test.

You might be interested in
A ball is thrown vertically upward from the ground with an initial velocity of 111 ft/sec. Use the quadratic function h(t) = −16
ddd [48]

Answer:

t=3.5 seconds

Step-by-step explanation:

Given

h(t) = −16t^2 + 111t + 0

h'(t)= -32t + 111

Maximum height occurs when h(t) = 0 and the ball begins to fall

h(t)= -32t + 111=0

-32t + 111=0

-32t=-111

Divide both sides by -32

t=3.46872

Approximately, t=3.5 seconds

Recall,

Maximum height occurs when h(t) = 0

h(t)= -32t + 111=0

= -32(3.46872)+111

= -110.99904+111

= 0.00096 ft

4 0
3 years ago
Please help me on this question.
scoundrel [369]

Answer:

f(1)=-48(-\frac{1}{4} )

= 12

f(n)=f(n-1)\:. (-\frac{1}{4} )

<u />

<u>OAmalOHopeO</u>

4 0
2 years ago
Read 2 more answers
IXL!! I WILL ADD BRAINLIST!
klio [65]

Answer:

-3,3.1, 3 2/10

Step-by-step explanation:

When you are putting different numbers from least to greatest, you need to put them in the same form...

First things first we should put -3 wayy up front. negative numbers are worth less than positive numbers.

Then we need to turn 3 2/10 into a decimal.

3 2/10 -------> 3.2

3.2 is more than 3.1

Thus, the order is

-3,3.1, 3 2/10

Hope this helps and have a nice day.

8 0
3 years ago
Read 2 more answers
Steve placed 5 weights on a scale during science class. If each weight
s2008m [1.1K]

Answer:

4

Step-by-step explanation:

If each weight is the same than we can simple multiply the weight of one by the number of weights there are

5(0.8)=4

3 0
3 years ago
Consider the function g(x) = (x-e)^3e^-(x-e). Find all critical points and points of inflection (x, g(x)) of the function g.
Elden [556K]

Answer:

The answer is "cirtical\  points \ (x,g(x))\equiv  (e,0),(e+3,\frac{27}{e^3})"

Step-by-step explanation:

Given:

g(x) = (x-e)^3e^{-(x-e)}

Find critical points:

g(x) = (x-e)^3e^{(e-x)}

differentiate the value with respect of x:

\to g'(x)= (x-e)^3 \frac{d}{dx}e^{e-r} +e^{e-r}  \frac{d}{dx}(x-e)^3=(x-e)^2 e^{(e-x)} [-x+e+3]

critical points g'(x)=0

\to (x-e)^2 e^{(e-x)} [e+3-x]=0\\\\\to e^{(e-x)}\neq 0 \\\\\to (x-e)^2=0\\\\ \to [e+3-x]=0\\\\\to x=e\\\\\to x=e+3\\\\\to x= e,e+3

So,

The critical points of (x,g(x))\equiv  (e,0),(e+3,\frac{27}{e^3})

7 0
3 years ago
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