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cestrela7 [59]
3 years ago
8

Use the distributive property to write an equivalent expression in simplest form. 9(4h+ 9m)

Mathematics
2 answers:
sammy [17]3 years ago
4 0

Answer:

36h+81m

Step-by-step explanation:

9*4h+9*9m=36h+81m

torisob [31]3 years ago
3 0

Answer:

36h + 81m

Step-by-step explanation:

<u>Step 1:  Distribute</u>

9(4h + 9m)

36h + 81m

Answer:  36h + 81m

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(1 x 106) - (8 x 109)<br> How do I solve it
choli [55]
First of all 1 x 106= 106, secondly 8 x 109= 872. Therefore you would subtract 872 from 106 and that’s your answer
5 0
3 years ago
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Please please helppp answer correctly !!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!!!!
marusya05 [52]

Answer:

holy.... that's a lot of variables.

4t+2s+w+u+x+v

4 0
3 years ago
PLEASE HURRY IM TIMED!!!
andriy [413]

<u>Answer-</u>

<em>A. Brandon’s sound intensity level is 1/4th as compared to Ahmad’s.</em>

<u>Solution-</u>

Given that, loudness measured in dB is

L=10\log \frac{I}{I_0}

Where,

I   = Sound intensity,

I₀ = 10⁻¹² and is the least intense sound a human ear can hear

Given in the question,

I₁ = Intensity at Brandon's = 10⁻¹⁰

I₂ = Intensity at Ahmad's  = 10⁻⁴

Then,

L_1=10\log \frac{I_1}{I_0}=10\log \frac{10^{-10}}{10^{-12}}=10\log \frac{1}{10^{-2}}=10\log 10^{2}=2\times10\log 10=20

L_2=10\log \frac{I_2}{I_0}=10\log \frac{10^{-4}}{10^{-12}}=10\log \frac{1}{10^{-8}}=10\log 10^{8}=8\times10\log 10=80

\therefore \frac{L_1}{L_2} =\frac{20}{80} =\frac{1}{4}

5 0
3 years ago
A first number plus twice a second number is 9. Twice the first number plus the second totals 27. Find the numbers
SOVA2 [1]
Create a a system of 2 equations: 2x + y = 27 and 2y + x = 9, with x being the first number and y being the second. solve for the two variables and you'll get the first number is 15 and the second is -3.
6 0
4 years ago
A rocket is fired with an initial vertical velocity of 40 m/s from a launch pad 45 m high, and its height is given by the formul
N76 [4]

Answer:

1) 125 meters

2) For 9 seconds.

Step-by-step explanation:

The rocket's height is given by the formula -5t^2+40t+45.

Notice that this is a quadratic.

Part 1)

Since this is a quadratic, the highest height the rocket goes will be the vertex of our quadratic. Remember that the vertex of a quadratic in standard form is:

(-\frac{b}{2a}, f(-\frac{b}{2a}))

So, let's identify our coefficients. The standard quadratic form is:

ax^2+bx+c

Therefore, in this case, our a is -5, b is 40, and c is 45.

So, let's find the x-coordinate of our vertex. Substitute 40 for b and -5 for a. This yields:

x=\frac{-(40)}{2(-5)}

Multiply and reduce. So:

x=-40/-10=4

Now, substitute 4 for t to find the height. So:

-5(4)^2+40(4)+45

Evaluate:

=-5(16)+40(4)+45

Multiply and add:

=-80+160+45=125\text{ meters}

Therefore, the highest the rocket goes up is 125 meters.

Part 2)

To find out for how much time the rocket is in the air, we can think about after how many seconds after launch will the rocket land.

If the rocket lands, the height h will be 0. So, we can set our expression equal to 0 and solve for t:

-5t^2+40t+45=0

First, let's divide everything by -5. This yields:

t^2-8t-9=0

We can factor:

(t+1)(t-9)=0

Zero Product Property:

t+1=0\text{ or } t-9=0

Solve for t:

t=-1\text{ or } t=9

In this case, since t is our time in seconds, -1 seconds does not make sense. So, we can remove -1 from our solution set.

Therefore, 9 seconds after launch, the rocket will touch the ground.

Therefore, the rocket was in the air for 9 seconds.

And we're done!

6 0
4 years ago
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