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Citrus2011 [14]
4 years ago
8

I need to know how much each would cost?

Mathematics
1 answer:
uranmaximum [27]4 years ago
5 0
1=$8.50, 2=$17, 3=$25.50, 4=$34
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Find all the zeros of the equation. -x^3-3x^2=6x+4
k0ka [10]

Answer:

The zeros of given expression -x^3-3x^2=6x+4 is -1, -1+i\sqrt{3} and -1-i\sqrt{3}

Step-by-step explanation:

Given expresssion is -x^3-3x^2=6x+4

To find zeros of given expression we have to equate the expression to zero.

ie., -x^3-3^2-6x-4=0

-(x^3+3x^2+6x+4)=0

x^3+3x^2+6x+4=0

By using synthetic division

-1  |  1    3    6    4

    |  0   -1   -2   -4

    |________________

       1    2   4    0

Therefore (x+1) is a  zero

Now the quadratic equation is x^2+2x+4=0

For quadratic equation ax^2+bx+c=0  we have

x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

Here a=1 ,b=2 and c=4 now substitute the values

x=\frac{-2\pm \sqrt{2^2-4(1)(4)}}{2(1)}

x=\frac{-2\pm \sqrt{4-16}}{2}

x=\frac{-2\pm \sqrt{-12}}{2}

x=\frac{-2\pm \sqrt{12i^2}}{2} where i^2=-1

x=\frac{-2\pm i \sqrt{4\times 3}}{2}

x=\frac{-2\pm i \sqrt{4}\sqrt{3}}{2}

x=\frac{-2\pm 2i\sqrt{3}}{2}

x=2\times\frac{(-1\pm i\sqrt{3})}{2}

x=-1\pm i\sqrt{3}

Therefore x=-1+i\sqrt{3}  and x=-1-i\sqrt{3}

Therefore the zeros are -1, -1+i\sqrt{3} and -1-i\sqrt{3}

4 0
4 years ago
Can someone help me I don't get it
Cerrena [4.2K]

Answer:

6a C; 6b C

8: b.2 and d.15/4

Step-by-step explanation:

6 0
3 years ago
22 less than 5 times a number f
Rasek [7]

Answer:

22-5f

Step-by-step explanation:

22 less then 5 would be 22-5 and then you have 5 times a number f so that would make it 5f so you would just attach the f to the 5. I hope this is helpful and is what you are looking for.

5 0
3 years ago
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True or false: f(x) represents a function.<br> A. True <br> B. False
pav-90 [236]

Answer:

A.) True

Step-by-step explanation:

A set of outputs and inputs becomes a function when there is only one output per input. In this case, each "x" value only has one "y" value, making it a function.

8 0
2 years ago
The base of S is the region enclosed by the parabola y = 5 ? 5x2 and the x-axis. Cross-sections perpendicular to the x-axis are
Dafna11 [192]

Answer:

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