Y = 5x - 13 ----------- (1)
5x + 2y = 19 --------- (2)
Sub (1) into (2):
5x + 2(5x -13) = 19
5x + 10x - 26 = 19
15x = 19 + 26
15x = 45
x = 3 -------- sub back into (1)
y = 5(3) - 13
y = 15 - 13
y = 2
Ans: x = 3, y = 2
Hmmm the object, is at rest, when dropped, so it has a velocity of 0 ft/s
the only force acting on the object, is gravity, using feet will then be -32ft/s²,
was wondering myself on -32 or 32.. but anyhow... we'll settle for the negative value, since it seems to be just a bit of convention issues
so, we'll do the integral to get v(t) then

when will it reach the ground level? let's set s(t) = 0

part B) check the picture below
Answer:
32 MPH
Step-by-step explanation:
MPH= Distance/Time
24/(3/4)= 24*4/3 = 96/3 = 32 MPH
Y=1/5x ! :) I hoped this helped ! Privately message me if you need help with anything else !!
Answer:
13 and 32
Step-by-step explanation:
let one number be x
Then the other number is x + 19 , then
x + x + 19 = 45
2x + 19 = 45 ( subtract 19 from both sides )
2x = 26 ( divide both sides by 2 )
x = 13
The 2 numbers are 13 and 13 + 19 = 32