2 years ago

FIRST PART OF MY LAST QUESTION ONLY FOR ONE PERSON TO uSE

Mathematics

1 answer:

SOVA2 [1]2 years ago

4 0

Answer:

Step-by-step explanation:

You just need to convert some of the mixed numbers so that they have a denominator (of the fraction part) as 8:

10 4/8 = 10 1/2

10 6/8 = 10 3/4

11 2/8 = 11 1/4

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Does this graph represent a function? Why or why not?

vlabodo [156]

Answer:

Step-by-step explanation:

In order for a graph to be a function, it has to only cross the vertical (up and down) lines that it covers once. Since this is an angle, it crosses all the lines in two different places, and isn't a function.

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3 years ago

Assume that you want to test the claim that the paired sample data come from a population for which the mean difference is μd =

swat32

Answer:

Test statistic, $t_{s} = -0.603$ (to 3 dp)

Step-by-step explanation:

Deviation, d = x -y

Sample mean for the deviation

$\bar{d} = \frac{\sum x-y}{n}$

$\bar{d} = \frac{(28-6) + (31-27)+(20-26)+(25-25)+(28-29)+(27-32)+(33-33)+(35-34)}{8} \\\bar{d} = -0.625$

Standard deviation: $SD = \sqrt{\frac{\sum d^{2} - n \bar{d}^2}{n-1} }$

$\sum d^{2} = (28-26)^2 + (31-27)^2 +(20-26)^2 +(25-25)^2 +(28-29)^2 +(27-32)^2 +(33-33)^2 +(35-34)^2\\\sum d^{2} = 63$

$SD = \sqrt{\frac{63 - 8 * (-0.625)^2}{8-1} }$

SD =2.93

Under the null hypothesis, the formula for the test statistics will be given by:

$t_{s} = \frac{ \bar{d}}{s_{d}/\sqrt{n} } \\t_{s} = \frac{- 0.625}{2.93/\sqrt{8} }$

$t_{s} = -0.6033$

6 0

3 years ago

Can someone please help

Dmitrij [34]

Answer:

1) a. 15ft

b. 6ft

c. 30ft

2) a. 16m

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2 years ago

Read 2 more answers

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nasty-shy [4]

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3 years ago

Combine the like terms to create an equivalent expression:<br> -2x-x+8

lara31 [8.8K]

Answer:

-3x+8

Step-by-step explanation:

-2x-x+8=

-3x+8

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2 years ago

FIRST PART OF MY LAST QUESTION ONLY FOR ONE PERSON TO uSE ​

FIRST PART OF MY LAST QUESTION ONLY FOR ONE PERSON TO uSE